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AleksandrR [38]
3 years ago
7

Why would putting argon and pottassium in order of there atomic masses be wrong

Chemistry
1 answer:
coldgirl [10]3 years ago
8 0
Putting them in that oder can be absolutely wrong becaus they are not in the same group of the periodic table
You might be interested in
For the following reaction,
jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

                               2CO   + O2      ⇒    2CO2

CO = 0.414 moles

O2 = 0.418

 

Process

theoretical ratio   CO/O2 = 2/1 = 1

experimental ratio  CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

                    2 moles of CO ---------------  2 moles of CO2

                    0.414 moles of CO ---------  x

                   x = (0.414 x 2) / 2

                   x = 0.414 moles of CO2

                   

5 0
3 years ago
______ will have a higher entropy than 50.0 g CO2 (g) at 56 oC.
Tomtit [17]
1) The more mass is the more entropy , because there are more particles, there is disorder.
2) Than higher temperature --- the more entropy.
3) Gas has more disorder than liquid, so gas has more entropy.
So, correct answer is E.
5 0
3 years ago
Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?
rodikova [14]
<span>Equation:2H2(g) + O2(g) → 2H2O(g)
</span><span>
Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.

</span>
4 0
2 years ago
Read 2 more answers
Will bromine react with sodium
denis-greek [22]
Yes. bromine and sodium iodide can react to form sodium bromine and free iodine
4 0
2 years ago
What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

Plugin the values as,

M2 = $\frac{150 \times 0.5}{60}

       = 1.25 M

So the molarity of the stock solution is 1.25 M.

4 0
3 years ago
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