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user100 [1]
3 years ago
12

Why does your boat float but not your ring?

Physics
1 answer:
Damm [24]3 years ago
5 0

The air that is inside a ship is much less dense than water. That's what keeps it floating! ... The closer the total density of the ship is to the density of the same volume of water, the greater the amount of the ship that will be in the water.

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What is the pathway of sound through fluids starting at the oval window through to dissipation of the sound waves at the round w
ruslelena [56]
Perilymph of scala vestibule; endolymph of cochlear duct; perilymph of scala tympani
6 0
3 years ago
A freight train rolls along a track with considerable momentum. If it rolls at the same speed but has twice as much mass, its mo
GREYUIT [131]

Answer:

doubled

Explanation:

<u>Step 1</u>. Linear momentum (p) = mass X velocity = mv

p = mv -----equation 1

<u>Step 2</u>. if the mass is now twice and speed is same

p = (2*m)v -----equation 2

solving equation 1 and 2 together,

p = mv = 2mv

p = 2

Therefore, its momentum is doubled

7 0
3 years ago
A 0.050 kg bullet strikes a 5.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off toge
natka813 [3]

Answer: 909 m/s

Explanation:

Given

Mass of the bullet, m1 = 0.05 kg

Mass of the wooden block, m2 = 5 kg

Final velocities of the block and bullet, v = 9 m/s

Initial velocity of the bullet v1 = ? m/s

From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve

m1v1 = (m1 + m2) v, on substituting, we have

0.05 * v1 = (0.05 + 5) * 9

0.05 * v1 = 5.05 * 9

0.05 * v1 = 45.45

v1 = 45.45 / 0.05

v1 = 909 m/s

Thus, the original velocity of the bullet was 909 m/s

3 0
3 years ago
The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?
dlinn [17]

Answer:

Force on the singly charged ion will be 12.6\times 10^{-13}N

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be E=8MN/C=8\times 10^6N/C

It is given that ion so charge on ion will be equal to e=1.6\times 10^{-19}C

We have to find the electric force on the ion

Electric force is equal to F=qE, here q is charge and E is electric field

So force on the charge will be equal to F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N

So force on the singly charged ion will be 12.6\times 10^{-13}N

7 0
4 years ago
A runner moving at a speed of 8.8m/s rounds a bend with a radius of 25m. what is the centripetal acceleration of the runner
nikitadnepr [17]
Radial acceleration is = v^2/r
Therefore (8.8m/s)^2/(25m)= 3.10m/s^2

Hope this helps you! Any questions please just ask! Thank you!
8 0
3 years ago
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