Answer:
No, they are not because when you stretch the rubber band you are deforming it but with the spring it is made to go up and down.
Explanation:
Answer:
a) initial position = 10m
b) average velocity = 30m/s
Explanation:
The general equation of a motion with constant velocity is given by:
(1)
So: initial position
v: average velocity
t: time
You have the following equation:
(2)
If you compare the equations (1) and (2) you obtain that:
hence:
a) initial position = 10m
b) average velocity = 30m/s
A single polarizer will stop 50% of the incoming light.
Answer:
its terminal velocity is 19.70 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
Explanation:
Firstly,
given that
m = 580g = 0.58kg
Area A = 0.11 * 0.22 = 0.0242m
g = 9.8
idensity constant p = 1.21 kg/m^3
the terminal velocity of the sphere Vt is ;
Vt = √ ( 2mg / pCA)
we substitute
Vt = √ ( (2*0.58*9.8) / (1.21*1*0.0242)
Vt = √ (11.368 / 0.029282)
Vt = √ ( 388.22)
Vt = 19.70 m/s
its terminal velocity is 19.70 m/s
What will be the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
The Velocity of the person is;
V2 = √ 2ax
V2 = √ ( 2 * 9.8 * 4 )
V2 = √ (78.4)
V2 = 8.85 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
Answer:
43.80°
Explanation:
The side of the equilateral triangle is given as 8 cm
The area of the equilateral triangle
Magnetic field
Magnetic flux
We know that
So