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emmainna [20.7K]
3 years ago
15

jim makes an electromagnet by wrapping a copper wire around a nail and then connecting it to a battery. if he brings the end of

the nail near a pile of paper clips, which of the following will happen?
Physics
2 answers:
Yakvenalex [24]3 years ago
8 0

the paper clips will be magnetically attracted to the nail

SIZIF [17.4K]3 years ago
7 0
The nail will have the ability to pull the pile of paperclips in a magnetic field. Meaning the nail will work as if it is a magnet

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Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul
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Answer:

The radius of coil 2 = 2.7 cm

Explanation:

The number of coils = 2

It is given that both carry equal current and rotates in the magnetic field.

The given radius of coil 1 = 4.0 cm

Coil 1 rotates = 0.21 T field

Coil 2 rotates = 0.45 T filed.

The radius of coil 2 need to be calculated.

Torque action on dipole is given byT =NIABsinθ

here T1 = T2

r1^{2} \times  B1 = r2^{2} \times B2 \\r2^{2} = 0.04 \times 0.04 \times \frac{0.21}{0.45} \\r2 = 0.027m   \ or \ 2.7 cm \\

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3 years ago
Which of the following are coefficients you could use in a balanced equation?
Novay_Z [31]

Answer: 1, 2, 6, 9

Explanation:

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When an ideal diatomic gas is heated at constant
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Q=∆U+W

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The newton is defined as the:
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The Newton is defined as the:

C. Force that can give a 1-kilogram mass an acceleration of 1m/sec squared.

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4 0
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The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

               \text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

             \text { Drag force }=k v^{2}

Where ,  

     k=\frac{1}{2} \rho C_{D} A (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

                   N_{i}=k v^{2}

After increase in speed, the final drag force will be  

                   N_{f}=k(2 v)^{2}

                   N_{f}=4 k v^{2}=4 N_{i}

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0
3 years ago
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