Answer:
3.60342 seconds
Explanation:
v = Initial velocity of snowball = 25 m/s
g = Acceleration due to gravity = 9.81 m/s²
= First angle = 75°
The second angle will be
Horizontal speed for first throw
Horizontal speed for second throw
Horizontal range is given by
Time period for first throw
Time period for second throw
The time difference is
The second ball should be thrown 3.60342 seconds later
The correct answer is 4 cm :)
1. An 8-kilogram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/s, how fast is it traveling?
momentum = mass x velocity
16 = 8 x velocity
velocity = 2 m/s
2.A beach ball is rolling in a straight line toward you at a speed of 0.5 m/sec. Its momentum is 0.25 kg•m/s. What is the mass of the beach ball?
momentum = mass x velocity
0.25 = m x 0.5
mass = 0.5 kg
3.A 4,000-kilogram truck travels in a straight line at 10.0 m/s. What is its momentum?
Momentum = (mass) x (speed) = (4,000) x (10) = 40,000 kilogram-meters/second
4.A 1,400-kilogram car is also traveling in a straight line. Its momentum is equal to that of the truck in the previous question. What is the velocity of the car?
40,000 kilogram-meters/second = 1400 x velocity
velocity = 28.6 m/s
5.Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s?
F1 = 8 x 0.2 / 10 = 0.16 N
F2 = 4 x 1.0 / 10 = 0.4 N ----> take more force
6.The momentum of a car traveling in a straight line at 20 m/s is 24,500 kg•m/s. What is the car’s mass?
24500 = mass x 20
mass = 1225 kg
7.Another pitcher throws the same baseball in a straight line. Its momentum is 2.1 kg•m/s. What is the velocity of the ball?
2.1 = 0.5 x velocity
velocity = 4.2 m/s
8 A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/s. What is the turtle’s momentum?
momentum = 1 x 0.01 = 0.01 kg m/s
Answer:
a)0.024
b)0.148
Explanation:
Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H
Given:
P(L) = 0.16
P(H) = 0.10
P(L n H) = 0.1 ·P( L u H )
Hence, P( L u H) = 10 ·P( L nH)
(a)
Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)
Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )
Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26
Hence, P(L n H) =
0.26/11=0.024
(b)
We know that condition probability P(H ║ L) = p(L n H)/P(L)
hence, P(H ║ L) =(0.26/11)/0.16 =0.148
Answer:
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