True or false: I should write partial charges on any polar bond within a molecule, even if the molecule as a whole is nonpolar

Chemistry

1 answer:

Julli [10]2 years ago

6 0

The answer of this statement is false because partial charge occurs only on polar bonds.

<h3>How I put partial charge on molecule?</h3>

I should write partial charges on any polar bond within a molecule, but not a molecule which whole is nonpolar because charge only occurs when the atom gains or loses electron.

So we can conclude that The answer of this statement is false because partial charge occurs only on polar bonds.

Learn more about polar here: brainly.com/question/545359

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In the reaction Mg(s) + 2HCl(aq) → H2(g) + MgCl2(aq), how many moles of hydrogen gas will be produced from 250.0 milliliters of

satela [25.4K]

Mg + 2HCl = H₂ + MgCl₂

n(HCl)=c(HCl)v(HCl)

n(H₂)=n(HCl)/2=c(HCl)v(HCl)/2

n(H₂)=3.0mol/L*0.2500L/2=0.375 mol≈0.38 mol

5 0

3 years ago

Read 2 more answers

How many grams of barium sulfate, BaSO 4 , be precipitated when 2.25 moles of sodium sulfate , Na 2 SO 3 , reacts with an excess

gulaghasi [49]

Answer:

525.1 g of BaSO₄ are produced.

Explanation:

The reaction of precipitation is:

Na₂SO₄ (aq) + BaCl₂ (aq) → BaSO₄ (s) ↓ + 2NaCl (aq)

Ratio is 1:1. So 1 mol of sodium sulfate can make precipitate 1 mol of barium sulfate.

The excersise determines that the excess is the BaCl₂.

After the reaction goes complete and, at 100 % yield reaction, 2.25 moles of BaSO₄ are produced.

We convert the moles to mass: 2.25 mol . 233.38 g/mol = 525.1 g

The precipitation's equilibrium is:

SO₄⁻² (aq) + Ba²⁺ (aq) ⇄ BaSO₄ (s) ↓ Kps

7 0

2 years ago

How many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas?

Marysya12 [62]

4 moles of water are produced

Explanation:

4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as $5H_{2} +2O_{2} --> 4H_{2} O + H_{2}$
This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.