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nataly862011 [7]
2 years ago
11

PLEASE HELP IM TAKING A TEST!!! Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2

, what is the limiting reactant?
a

FeS2


b

Fe2O3


c

O2


d

SO2
Chemistry
1 answer:
chubhunter [2.5K]2 years ago
7 0

Answer:

c-)O2

Explanation:

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Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Lo
Fiesta28 [93]

The complete question is: Match the following; Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Long-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.

The answer

Disulfide Bonds (Covalent interactions not found in all proteins.)

Peptide Bonds (Covalent interactions found in all proteins.)

Long-range interactions (Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.)

Hydrophobic core. (Non-covalent interaction formed primarily on the interior of water-soluble proteins.)

Explanation:

The phrases have been given the right meaning enclosed in a parentheses. The should be matched accordingly as presented.

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How many moles of Ca3 (PO4)2 can be formed when 1.9 moles of CaCO3 react with 2.7 moles of FePO4?
Nonamiya [84]

Answer:-

0.633 moles

Explanation:-

The first step to solving this problem is to write the balanced chemical equation.

The balanced chemical equation for this reaction is

3 CaCO3 + 2 FePO4 = Ca3(PO4)2 + Fe2(CO3)3

From the balanced chemical equation, we can see

3 moles of CaCO3 react with 2 moles of FePO4.

In the question we are told there are 1.9 moles of CaCO3.

So 1.9 moles of CaCO3 react with (2 moles x 1.9 moles )/ 3 moles= 1.267 moles of FePO4.

The question tells us there are 2.7 moles of FePO4.

So there is excess FePO4.

Thus our limiting reagent is CaCO3. It will determine how much Ca3(PO4)2 is formed.

From the balanced chemical equation, we can see

3 moles of CaCO3 gives 1 mole of Ca3(PO4)2

1.9 moles of CaCO3 gives (1 moles x 1.9 moles ) / 3 moles= 0.633 moles of Ca3(PO4)2.

0.633 moles of Ca3 (PO4)2 can be formed when 1.9 moles of CaCO3 react with 2.7 moles of FePO4

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