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PolarNik [594]
2 years ago
10

In the rocket, what is the equal and opposite reaction?

Physics
1 answer:
netineya [11]2 years ago
7 0

Answer:

see below

Explanation:

Gases flying out at high velocity out the back  

  rocket flying forward

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I’m sorry this is a quiz and we’re correcting it and I still don’t get it anyone know ?
kotegsom [21]

Answer:

3.0M

Explanation:

Thats two wavelengths,not one.

Pretty honest mistake I would've made the same if I was rushing

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3 years ago
HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
OLga [1]
At the top, due to the fact that POTENTIAL energy is Stored energy.
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3 years ago
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Which three temperature readings all mean the same thing?
Drupady [299]

Answer : The correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Explanation :

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

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3 years ago
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Why does the Moon appear red during a lunar eclipse?
dem82 [27]

Answer:

Image result for Why does the Moon appear red during a lunar eclipse?

A lunar eclipse takes place when the sun, Earth and moon line up in space. The moon passes through Earth's shadow. ... Bottom line: The moon can look red during a total lunar eclipse because of sunlight that's filtered and refracted by Earth's atmosphere

6 0
2 years ago
A probe orbiting Venus exerts a gravitational force of 2.58 × 10^3 N on Venus. Venus has a mass of 4.87 × 10^24 kg. The mass of
Crazy boy [7]
So this is the info that's given to us:
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N

Now we can use this equation to solve: f_g= \frac{Gm_1m_2}{r^2}

You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :

2.58 x 10^3 = \frac{6.67x10^{-11} * 4.87 x 10^{24} * 655}{r^{2}} 

As you can see we only have one variable, so we solve for r! 

r = 9.08 x 10^6 km

I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>

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