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Anuta_ua [19.1K]
3 years ago
13

What happens to acceleration if forces are balanced

Physics
2 answers:
Arturiano [62]3 years ago
8 0
There will be 0 acceleration
Vikentia [17]3 years ago
5 0

Answer:

No acceleration.

Explanation:

If the forces are Balanced it means they are in equilibrium and there will be  no net force, therefore the object will not accelerate and the velocity will remain constant.

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If a body has 60N weight what will be its mass on moon
zvonat [6]
If the object weighs 60N on Earth, then its mass is 6.12 kilograms.

If it weighs 60N on the moon, then its mass is 36.97 kilograms.

Whatever its mass is in one place, it has the same mass in any other place. Mass doesn't depend on location, but weight does.
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3 years ago
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If the new moon happens on January 15th, what shape will it be on February 6th?
Jobisdone [24]

-- From January 15 to February 6 is a period of 22 days.

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3 years ago
Which example possesses mechanical potential energy?. A. a taut guitar string. B. an oscillating pendulum. C. a roller coaster r
NeTakaya
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The taut guitar string haspotencial energy which we can see in action.</span>  <span>· so option a is correct.</span>
7 0
3 years ago
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A coin is thrown with a velocity of 0 m/s down a dry well and hits bottom in 1.2s, what’s the depth of the well?
pentagon [3]

Answer:

The well is 7.1 meters deep.

Explanation:

The formula to use here is the distance in a uniformly accelerated motion:

d = \frac{1}{2}at^2+v_0t+d_0

where d stands for distance, t for time, a for acceleration, v0 and d0 for initial velocity and distance, respectively. Since the initial distance and velocity are both zero, we are left with the first term. The coin is in free fall and so it is accelerated by gravity:

d = \frac{1}{2}at^2= \frac{1}{2}gt^2=\frac{1}{2}9.8\frac{m}{s^2}1.2^2s^2=7.1m

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3 years ago
A 0.59 kg bullfrog is sitting at rest on a level log. how large is the normal force of the log on the bullfrog?
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<span>The bullfrog is sitting at rest on the log. The force of gravity pulls down on the bullfrog. We can find the weight of the bullfrog due to the force of gravity. weight = mg = (0.59 kg) x (9.80 m/s^2) weight = 5.782 N The bullfrog is pressing down on the log with a force of 5.782 newtons. Newton's third law tells us that the log must be pushing up on the bullfrog with a force of the same magnitude. Therefore, the normal force of the log on the bullfrog is 5.782 N</span>
7 0
3 years ago
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