Answer:1
Explanation:
Let the heat given by flame be .
Let be the mass of water in case 1.
Let be the mass of water in case 2.
Let Δ be the temperature difference in case 1.
Let Δ be the temperature difference in case 2.
Let be the volume of water in case 1.
Let be the volume of water in case 2.
Let be the density of water.
Let be the specific heat of water.
Given,
Δ
Since the same heat is given to water in both the cases,
Δ
Δ
So,Δ=Δ
Since mass is product of volume an density,
Δ=Δ
Δ
So,Δ
Answer:
Explanation:
Intake heat, QH = 100 J
output heat, Qc = 20 J
Work, W = 80 J
TH = 100°C = 373 K
Tc = 10°C = 283 K
TH/ Tc = 373 / 283 = 1.318
QH/Qc = 100 / 20 = 5
for a heat engine, those ratios should be same. so temperature is not correct.
Answer:
False
Explanation:
The object could be in a constant velocity and the sum of both the external torques and the external forces on an object is zero. Newton's first law states that when the total net force is 0 or there is zero force, the object could be at rest OR remain in constant velocity. It's not necessary at rest.
Deciliter = 1/10 of a liter
Milliliter = 1/1000 of a liter
So, there are 100 milliliters in one deciliter
Answer:
42.4 Npa
Explanation:
Explanation is attached in the picture below