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N76 [4]
3 years ago
7

When humans look at the sky, it appears blue, but the Sun appears yellow. What causes this phenomenon?

Physics
2 answers:
Lesechka [4]3 years ago
8 0
I believe that the answer is <span>C. The atmosphere scatters blue light more than yellow light.</span>
Dmitrij [34]3 years ago
8 0
D. the atmosphere reflects all the of the colors of light 
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Calculate the net force being applied to the objects. Include SIZE and DIRECTION.
guajiro [1.7K]
Juice WRLD 999 ,........................
3 0
3 years ago
2. Who bombarded molybdenum with atomic number (Z=42) with fast moving<br>neutrons?<br>​
Dominik [7]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete, however Molybdenum-99 (⁹⁹Mo) is produced by bombarding Molybdenum-98 (⁹⁸Mo) with fast moving neutrons (¹₀n) as shown below

⁹⁸₄₂Mo + ¹₀n ⇒  ⁹⁹₄₂Mo + ⁰₀γ

This reaction is a nuclear caption reaction (which occurs in a nuclear reactor) for the production of Molybdenum-99 (⁹⁹Mo) which serves as a "precursor" for the production of medically viable/ Clinical Grade Technutium-99m (⁹⁹Tc) through Ion-exchange technique.

3 0
3 years ago
An object is dropped from a​ tower, 400 ft above the ground. The​ object's height above ground t seconds after the fall is ​s(t)
Paul [167]

Answer: v= 160ft/s

a=32ft/s^2 constant

Explanation:

s(t)=400-16t^2 derivative of position is velocity v(t) and derivative of velocity is acceleration a(t) so let s(t)=0 to find the time of flight to reach the ground and take the two derivatives and use the time found and solve. Also acceleration is a constant as it’s gravity.

0=400-16t^2

400=16t^2

25=t^2

t=5s

ds/dt=v(t)=0-32t

dv/dt=a(t)=-32 constant(gravity)

v(t)=-32(5s)= -160ft/s negative sign is only showing direction

7 0
3 years ago
Resistor 1 has a resistance of 10 N and
Arlecino [84]

Answer:

Resistance 2.

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

V = IR

Where;

  • V represents voltage measured in voltage.
  • I represents current measured in amperes.
  • R represents resistance measured in ohms.

<u>Note</u>: Voltage is the same as potential difference.

Given the following data;

Resistance 1  = 10 Ohms

Current 1 = 3 Amperes

Potential difference 1 = current * resistance

Potential difference 1 = 3 * 10

<em>Potential difference 1 = 30 V</em>

To find the potential difference in 2;

Resistance 2 = 5 Ohms

Current 2 = 10 Amperes

Potential difference 2 = 10 * 5

<em>Potential difference 2 = 50 V</em>

Therefore, Resistance 2 has greater potential difference.

5 0
2 years ago
a current of 1.80 a flows in a wire. how many electrons are flowing past any point in the wire per second?
liubo4ka [24]

Any point in the wire has 1.12 x 10^{19}. electrons flow per second.

<h3>What causes a current in a wire?</h3>
  • Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.
  • A free electron is drawn to a proton to become neutral if an electron is added to the wire.
  • Lack of electrons can result from pushing electrons out of their orbits.
  • Electric current is the name given to the constantly moving electrons in wire.

The current is the quantity of charge Q flowing through a certain point of the wire in a time interval of \Delta t.

I = \frac{Q}{\Delta t}.

by using this relationship

I=1.80 A, we can find the charge passing any point in the wire in 1 second:

Electric Charge, Q = 1.80 C.

To find how many electrons corresponds to this charge, we should divide this value by the charge of a single electron

charge of the electron = 1.6 x 10^{-19} C.

No. of Electrons = Q/q = \frac{1.80}{1.6* 10^{-19}}= 1.12 x 10^{19}.

To learn more about Electric current   refer,

brainly.com/question/9467901

#SPJ4

4 0
1 year ago
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