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White raven [17]
1 year ago
6

2) What did Rutherford discover in his experiment? a) nucleus b) electrons c) neutrons

Physics
1 answer:
OlgaM077 [116]1 year ago
5 0
A) nucleus because some aims reflected off the gold foil proving that there was something bigger inside the atom hence discovering the nucleus
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A wooden plaque is in the shape of an ellipse with height 30 centimeters and width 22 centimeters. Find an equation for the elli
Volgvan

Answer:

Explanation:

height of Ellipse =30 cm  

i.e. 2 a=30

Width of Ellipse =22 cm

i.e. 2 b=22

Equation of a vertical Ellipse is

\frac{x^2}{b^2}+\frac{y^2}{a^2}=1

a=15 ,b =11

\frac{x^2}{11^2}+\frac{y^2}{15^2}=1

at y=4 cm

\frac{x^2}{11^2}+\frac{4^2}{15^2}=1  

x=\frac{11}{15}\times \sqrt{15^2-4^2}

x=10.6 cm  

5 0
2 years ago
How does the force of gravity between two bodies change when the distance between them doubles? 1. unable to determine; the mass
Rzqust [24]
6. Drop to one quarter of its original value
7 0
3 years ago
Which body is in equilibrium?
sergey [27]
"(1) a satellite moving around Earth in a circular <span>orbit" is the only option from the list that describes an object in equilibrium, since velocity and gravity are working together to keep the orbit constant. </span>
6 0
2 years ago
Read 2 more answers
Bob walks 370 m south, then jogs 410 m southwest, then walks 370 m in a direction 28 degrees east of north.
wlad13 [49]
We will measure all angles from West, the negative x-axis and divide the journey into 3 parts:
P1 = 370y
P2 = 410cos(45)x + 410sin(45)y = 290x + 290y
P3 = 370cos(270 - 28)x + 370sin(270 - 28) = -174x - 327y

Overall displacement:
x = 290 - 174 = 116 m
y = 370 + 290 - 327 = 333 m

displacement = √(116² + 333²)
= 353 m

Direction:
tan(∅) = y/x
∅ = tan⁻¹ (333 / 116)
∅ = 70.8° from West.
5 0
3 years ago
Read 2 more answers
Two identical charges q placed 2.0 mapart exert forces of magnitude 4.0 N on each other What is the value of the charge q? a) q
katen-ka-za [31]

Answer:

c) 4.2*10^{-5}C

Explanation:

Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:

F=\frac{kq_{1}q_{2}}{r^{2}}

where k is a proportionality constant with the value k=9*10^{9}\frac{Nm^{2}}{C^{2}}

In this case q_{1}=q_{2}=q, so we have:

F=\frac{kq^{2}}{r^{2}}

Solving the equation for q, we have:

kq^{2}=Fr^{2}

q^{2}=\frac{Fr^{2}}{k}

q=\sqrt{\frac{Fr^{2}}{k}}

Replacing the given values:

q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}

q=4.2*10^{-5}C

3 0
3 years ago
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