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2 years ago

Convert 100 Newton into dyne

Physics

2 answers:

netineya [11]2 years ago

7 0

It would actually be 10 million dyne

Inga [223]2 years ago

5 0

Answer:10000000

Explanation:

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Debbie plotted a graph to show how the mass of aluminium rivets affected the distance the cup moved down.

Elan Coil [88]

Answer:

Explanation:

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2 years ago

Although wave power does not produce pollution, some people may not want to invest in it because it is _____. 100 percent renewa

notka56 [123]

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6 0

2 years ago

Read 2 more answers

Examine the scenario.

vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

$a=\frac{v-u}{t}$

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

$a=\frac{40 km/h-0}{5 s}=8 km/h/s$

And since the sign is positive, the direction is the same as the velocity (south).

7 0

3 years ago

Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

$\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}$

Where U is potential energy and K is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

$\displaystyle U_i = K_f$

Substitute and solve for final velocity:
$\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\ 2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ & =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}$

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0

1 year ago

A 2.0-kg block sliding on a rough surface is attached to one end of a horizontal spring (k = 200 N/m) which has its other end fi

earnstyle [38]

Answer:

The speed is 3.87 m/s

Explanation:

The total work is equal to the change to kinetic energy:

Wtotal = ΔEk

Wspring + Wfriction = Ekf - Eki

Eki = 0

$-(\frac{1}{2} kd^{2} )-(fk*m*g*d^{2} )=\frac{1}{2} m(v^{2} -v_{i} ^{2} )$

Where

k = 200 N/m

d = 10 cm = 0.1 m

fk = 0.15

m = 2 kg

g = 9.8 m/s²

vi = 4 m/s

Replacing and clearing v:

$-(\frac{1}{2} *200*0.1^{2} )-(0.15*2*9.8*0.1^{2} )=\frac{1}{2} *2*(v^{2} -4^{2} )\\-1-0.0294=v^{2} -16\\v=\sqrt{-1-0.0294+16} =3.87m/s$

3 0

2 years ago

Convert 100 Newton into dyne​

Convert 100 Newton into dyne