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ddd [48]
1 year ago
12

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat given to the system in thes

e steps are Q{1} = 1000J, Q{2} = - 800J, Q{3} = 450J , Q{4} = - 200 J respectively. The efficiency of cycle is nearly
Need full Explanation ! Answer is already marked in attachment just need the explanation or the way to reach the answer . ​

Physics
1 answer:
Mashcka [7]1 year ago
6 0

Answer:

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What are neglible weights. Definition? ​
Alex

Answer:

Negligible weights is a change so minor or insignificant to be deemed to have no effect on weight or balance.

4 0
2 years ago
A rocket has a mass of 156,789 kg and is traveling at 45.6 m/s. How much kinetic energy does the rocket
Flura [38]

Explanation:

K.E =1/2 mv^2

=1/2(156789)(45.6)^2

=78,394.5 × 2,079.36

=163,010,387.52 kg m/s

This should be your answer.

7 0
2 years ago
The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size aa ba
tester [92]

Answer:

3 volts

Explanation:

Number of turns in primary coil = N_{p} = 100

Number of turns in secondary coil = N_{s} = 200

Voltage across primary coil = V_{p} = 1.5 volts

Voltage across secondary coil = V_{s} = ?

In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.

\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }\\

Using the given values, we get:

\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3

Thus, the voltage measure across secondary coil would be 3 volts

4 0
3 years ago
An insulated Thermos contains 140 cm3 of hot coffee at 85.0°C. You put in a 15.0 g ice cube at its melting point to cool the cof
Pavel [41]

Answer:

T = 69^o C

Explanation:

Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes

So here we have

Q_{ice} = Q_{coffee}

now since ice cubes are added into coffee when it is at melting temperature

So here we can say that final temperature of coffee is T degree C

Now we have

m_1L + m_1c_1\Delta T_1 = m_2c_2\Delta T_2

here we have

m_1 = 15 gram

L = 333 kJ/kg = 333 J/g[/tex]

c_1 = c_2 = 4186 J/kg C = 4.186 J/g C

\Delta T_1 = T - 0

\Delta T_2 = 85 - T

now we have

15(333) + 15(4.186)(T - 0) = 140(4.186)(85 - T)

4995 + 62.79T = 49813.4 - 586.04T

648.83 T = 44818.4

T = 69^o C

6 0
3 years ago
If you apply a force of 100 N to the level, how much force is applied to lift the crate?
Kaylis [27]
I believe that the answer is B. 133 N
4 0
3 years ago
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