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ZanzabumX [31]
3 years ago
6

Create an array of 10 size and assign 10 random numbers. Now find the sum of the array using for and while loop.

Engineering
1 answer:
Simora [160]3 years ago
6 0

Answer:

10

Explanation:

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A museum has three rooms, each with a motion sensor (m0, m1, and m2) that outputs 1 when motion is detected. At night, the only
nordsb [41]

Answer:

a) see attachment

b) A= m0m1+ m1m2+ m0m2

see attachment for K-map

c) see attachment

Explanation:

a) see attachment for truth table

b) see attachment for k-map

A= m0m1+ m1m2+ m0m2

c) see attachment for gate level circuit

4 0
3 years ago
Who invented engineering first?​
astra-53 [7]

Explanation:

The earliest civil engineer known by name is Imhotep. As one of the officials of the Pharaoh, Djosèr, he probably designed and supervised the construction of the Pyramid of Djoser (the Step Pyramid) at Saqqara in Egypt around 2630–2611 BC.

8 0
3 years ago
1. A wood board is one of a dozen different parts in a homemade robot kit. The width, depth, and height dimensions of the board
otez555 [7]

Answer:

183.75 cubic inches.

Explanation:

The volume of the wood board is determine by means of this expression:

V = w \cdot h \cdot l

By replacing variables:

V = (7.5 in) \cdot (14 in) \cdot (1.75 in)\\V = 183.75 in^{3}

3 0
3 years ago
A six-lane freeway (three lanes in each direction) with a 5.5% uphill grade 1.5 miles long has 10-ft lanes and obstructions 5 ft
sertanlavr [38]
The answer would be:
A. LOS B
4 0
3 years ago
Read 2 more answers
What is the impedance of a 5μF capacitor at a frequency of 500Hz? What is the impedance of a60mH inductor at this frequency?
choli [55]

Answer:

1) 63.66 ohm

2) 188.49 ohm

Explanation:

Data provided in the question:

Part 1

Capacitance, C = 5μF = 5 × 10⁻⁶ F

Frequency = 500 Hz

Now,

Impedance = \frac{1}{2\times\pi\times f\times C}

or

Impedance = \frac{1}{2\times\pi\times500\times5\times10^{-6}}

or

Impedance = 63.66 ohm

Part 2

Inductance = 60 mH = 60 × 10⁻³ H

Frequency = 500 Hz

Now,

Impedance for an inductor = 2πfL

thus,

Impedance = 2 × π × 500 × 60 × 10⁻³

= 188.49 ohm

4 0
3 years ago
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