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7nadin3 [17]
3 years ago
12

A refrigerator has a cooling load of 50 kW. It has a COP of 2. It is run by a heat engine which consumes 50 kW of heat to supply

the necessary power to the refrigerator. The efficiency of the heat engine is:________________.
Engineering
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

50%

Explanation:

<u>Given information</u>

Cooling load=50 kW

COP=2

Consumption=50 kW

<u>Calculations</u>

Revised input is given by cooling load/COP=50/2=25 kW

Efficiency= Work output/ Revised input=25/50=0.5

Efficiency=0.5*100=50%

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Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying th
aleksandr82 [10.1K]

Answer:

# kelvin_to_celsius function is defined

# it has value_kelvin as argument

def kelvin_to_celsius(value_kelvin):

   # value_celsius is initialized to 0.0

   value_celsius = 0.0

   

   # value_celsius is calculated by

   # subtracting 273.15 from value_kelvin

   value_celsius = value_kelvin - 273.15

   # value_celsius is returned

   return value_celsius

   

# celsius_to_kelvin function is defined

# it has value_celsius as argument

def celsius_to_kelvin(value_celsius):

   # value_kelvin is initialized to 0.0

   value_kelvin = 0.0

   

   # value_kelvin is calculated by

   # adding 273.15 to value_celsius

   value_kelvin = value_celsius + 273.15

   # value_kelvin is returned

   return value_kelvin

   

value_c = 0.0

value_k = 0.0

value_c = 10.0

# value_c = 10.0 is used to test the function celsius_to_kelvin

# the result is displayed

print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = 283.15

# value_k = 283.15 is used to test the function kelvin_to_celsius

# the result is displayed

print(value_k, 'is', kelvin_to_celsius(value_k), 'C')

Explanation:

Image of celsius_to_kelvin function used as guideline is attached

Image of program output is attached.

4 0
3 years ago
What application of bioengineering uses principles of electronics and computer science to design products?
Flauer [41]

The application of electro bioengineering uses principles of nick and computer science to design products is application of electrical engineering principles to biology, medicine, conduct, or health.

<h3>What is Bioelectronics?</h3>
  • Bioelectronics is the application of electrical engineering principles to biology, medicine, conduct, or health.
  • It advances the fundamental concepts, creates knowledge for the molecular to the organ techniques levels, and develops creative devices or methods for the deterrence, diagnosis, and treatment of disease, for patient rehabilitation, and for improving health.
  • Bio electromagnetics, instrumentation, neural networks, robotics, and detector technologies are some of the disciplines necessary to develop new knowledge and creations in this area.
  • A keystone of this research area is the building of and real-world devices and systems.
  • Onsite facilities for prototyping and testing instrumentation systems, fabricating and measuring the performance of implantable devices, and making robotic prostheses, are readily available.
  • New detectors and sensor arrays are microfabricated in a 2,000 sq ft cleanroom.

To learn more about Bioelectronics, refer to:

brainly.com/question/21819443

#SPJ4

4 0
2 years ago
• ¿Qué les reclamó Dios al pueblo?<br> • ¿Qué consecuencias hubo?
HACTEHA [7]

a quien alos israelitas

8 0
3 years ago
You have the assignment of designing color codes for different parts. Three colors are used on each part, but a combination of t
Masja [62]

Answer:

7 available

Explanation:

Since 3 colors are available r = 3

Total combination = 35

nCr = 35 ---1

nCr = n!/(n-r)!r!---2

We put equation 1 and 2 together

n-1)(n-2)(n-3)!/n-3)! = 35x 3!

We cancel out (n-3)!

(n-1)(n-2) = 210

7x6x5 = 210

nC3 = 35

7C3 = 35

So If there are 35 combinations, 7 colors are available.

Thank you!

3 0
3 years ago
1. 6.1 PSPICEMULTISIM The current in a 50μH inductor is known to be iL=18te−10tAfor t≥0. 1. Find the voltage across the inductor
Andre45 [30]

Answer:

a. Voltage across the inductor for t > 0 is 0.9e^-10t(1-10t)

b. Power = -59.3μW

c. Inductor is delivering power.

d. Energy = 5934.3nJ

e. Time = 100ms; Energy = 1095941.025nJ

Explanation:

Given

Current; iL=18te^(−10t)A or t≥0.

L.= inductor = 50μH

a. The voltage, V across the inductor for t>0 is calculated as follows;

V = L(di/dt)

Where L = 50μH

di/dt = 18(e^-10t + (-10)te^-10t)

di/dt = 18e^-10t(1 - 10t)

Substitute 50μH for L and 18e^-10t(1 - 10t) for di/dt in V = L(di/dt)

V = 50μH * 18e^-10t(1 - 10t)

V = 50 * 10^-6(18e^-10t(1 - 10t))

V = 0.9e^-10t(1-10t)

Hence, the voltage across the inductor for t > 0 is 0.9e^-10t(1-10t)

b. Find the power (in microwatts) at the terminals of the inductor when t=200 ms.

Given that t = 200ms = 200 * 10^-3s = 0.2s

Power, p is calculated using the following formula;

p = Li(di/dt)

p = 50 * 10^-6(18te^-10t)18e^-10t(1-10t)

p = 50 * 10^-6 * (18 * 0.2 * e^-(10*0.2)) * (18 * e^(-10 * 0.2) * (1-10*0.2)

p = -5.93E5W

p = -59.3μW

c. Is the inductor absorbing or delivering power at 200 ms?

Because of the negative sign, the inductor is delivering power.

d. Find the energy (in microjoules) stored in the inductor at 200 ms.

Energy is calculated as ½Li²

= ½ * 50 * 10^-6 * (18te^-10t)²

= ½ * 50 * 10^-6 * (18 * 0.2 * e ^ (-10 * 0.2))²

= 0.0000059342669999498J

= 5934.3nJ

e. Find the maximum energy (in microjoules) stored in the inductor and the time (in milliseconds) when it occurs.

Calculating the derivation in (a)

di/dt = 0

18e^-10t(1-10t) = 0

1 - 10t = 0

-10t = -1

t = 1/10

t = 100ms

To calculate the energy, first we need to calculate the current

I(t=100) = 18 * 0.1 * e^(-10(0.1)

I = 0.662182994108596

I = 6621.82mA

The energy is calculated as follows;

w = ½ * 50 * 10^-6 * (6.621)²

w = 0.001095941025

w = 1095941.025nJ

8 0
3 years ago
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