The answer is 3.63. seconds.
Second order reaction is the reaction in which the rate of reaction depends on either the concentration of two reactant species or on the two times the concentration of single reactant species.
What is the integrated rate law for the second-order reaction?
- The integrated rate law that relates the concentration, time and rate constant for the second-order reaction is:
![\frac{1}{[A]} =\frac{1}{[A]_{0} } +kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D%20%2Bkt)
Where
![\[\begin{array}{l}{\rm{[A] - concentration\ of\ reactant\ A\ at\ time\ t}}\\{{\rm{[A]}}_0}{\rm{ - initial\ concentration\ of\ reactant\ A}}\\{\rm{t - time}}\\{\rm{k - rate\ constant}}\end{array}\]](https://tex.z-dn.net/?f=%5C%5B%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crm%7B%5BA%5D%20%20-%20%20concentration%5C%20of%5C%20reactant%5C%20A%5C%20at%5C%20time%5C%20t%7D%7D%5C%5C%7B%7B%5Crm%7B%5BA%5D%7D%7D_0%7D%7B%5Crm%7B%20-%20%20initial%5C%20concentration%5C%20of%5C%20reactant%5C%20A%7D%7D%5C%5C%7B%5Crm%7Bt%20-%20time%7D%7D%5C%5C%7B%5Crm%7Bk%20%20-%20%20rate%5C%20constant%7D%7D%5Cend%7Barray%7D%5C%5D)
- Now, in the given question,
k = 
![[NO_{2} ]= 0.62\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D%3D%200.62%5C%20M)
![[NO_{2} ]_{0} = 0.28\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D_%7B0%7D%20%3D%200.28%5C%20M)
- Thus, using the rate law, the time is calculated as-
Therefore,
- Hence, the it would take 3.63 seconds for the concentration of
to decrease from 0.62 M to 0.28 M if the reaction is second order.
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The correct answer is A.
B is incorrect because that only applies to nuclear fission.
C is incorrect because it only applies to nuclear fusion.
D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,
Answer:
-5.51 kJ/mol
Explanation:
Step 1: Calculate the heat required to heat the water.
We use the following expression.
where,
- c: specific heat capacity
- m: mass
- ΔT: change in the temperature
The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.
Step 2: Calculate the heat released by the methane
According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero
Qc + Qw = 0
Qc = -Qw = -22.0 kJ
Step 3: Calculate the molar heat of combustion of methane.
The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.
