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Aleks04 [339]
3 years ago
7

A long non-conducting hollow cylinder with inner radius, ri and outer radius, r2 is charged with a uniform positive charge with

a charge density ?. (a) Use Gauss's Law in differential form for regions outside the cylinder (r >r2) to show that the electric field decreases as 1/r (note that no marks will be awarded for using Gauss's Law in integral form).
Physics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:yup

Explanation:mhmm

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Can anyone help me I will give you 30 points
Aleonysh [2.5K]

Answer:

1) ELECTRO MAGNET

2) B

3) -AMOUNT OF ELECTRICITY OF THE POWER SOURCE

- AMOUNT OF COIL WRAPPED UP TO THE NAIK

-CONDUCTIVITY OF THE MEDIUM

3 0
4 years ago
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
BabaBlast [244]

Answer:

-\frac{8\pi}{3}rad/s^2

Explanation:

To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

\omega_f^2-\omega_i^2=2\alpha\theta

Where for definition,

\omega_i = \frac{\theta}{t}

The number of revolution (\theta)was given by 20 times, then

\omega_i = \frac{20*2pi}{5}

\omega = 8\pi rad/s

We know as well that the salad rotates 6 more times, therefore in angle measurements that is

\theta = 6*2\pi rad = 12\pi rad

The cook at the end stop to spin, then using our first equation,

0-8\pi = 2\alpha (12\pi)

re-arrange to solve\alpha ,

\alpha = \frac{-8\pi}{2*12\pi}

\alpha = -\frac{8\pi}{3}rad/s^2

We can know find the required time,

\omega_f-\omega_i = \alpha t

Re-arrange to find t, and considering that \omega_f=0

t= \frac{\omega_i}{\alpha}

t=\frac{-8\pi}{-8\pi/3}

t=3s

Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of -\frac{8\pi}{3}rad/s^2

6 0
3 years ago
Read 2 more answers
Does a race car driver need a faster reaction time then someone driving in a school zone explain your answer
rosijanka [135]
Answer:
Yes, the race car driver needs a faster reaction time than someone driving in a school zone.

Explanation.
For the sake of argument, let us consider
(i) a person driving at 35 mph in a school zone (as a normal driver);
(ii) a person driving at 60 mph in a school zone (as a racing driver).

Suppose a blind pedestrian crosses the road 0.1 miles (about 500 feet)  in front of the driver.
The time before the normal driver hits the pedestrian is
(0.1 /35)*3600 =  10.3 seconds.
The time before the racing driver hits the pedestrian is
(0.1/60)*3600 = 6 seconds.

Because a reaction time of 6 seconds may be insufficient to avoid hitting the pedestrian, the racing driver needs a faster reaction time than the normal driver.
6 0
4 years ago
A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive w
Tresset [83]
2,900 N is the answer if you need an explanation tell me and i will comment the explanation
8 0
4 years ago
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Samara stands on the ground. Gravity is applying a force to pull her body to the ground while the ground is applying the same am
Ierofanga [76]
Mhm nice question gimmie a sec
8 0
3 years ago
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