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Aleks04 [339]
3 years ago
7

A long non-conducting hollow cylinder with inner radius, ri and outer radius, r2 is charged with a uniform positive charge with

a charge density ?. (a) Use Gauss's Law in differential form for regions outside the cylinder (r >r2) to show that the electric field decreases as 1/r (note that no marks will be awarded for using Gauss's Law in integral form).
Physics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:yup

Explanation:mhmm

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When a magnet is moved through a coil of wire, an electric current is generated in the coil because
evablogger [386]

Answer:When a magnet is moved through a coil of wire, an electric current is generated in the coil because

Explanation: the magnet is pushing and pulling on the coils to make it move.

6 0
3 years ago
How many feet does a No. 2 pencil last?
Ray Of Light [21]

Answer:45,000

Explanation:

:TIL the average pencil holds enough graphite to draw a line about 35 miles long or to write roughly 45,000 words

6 0
2 years ago
A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi
LiRa [457]

Answer:

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

Q_{in} - W_{out} = \Delta E

Where:

Q_{in} - Heat absorbed by the gas, measured in joules.

W_{out} - Work done by the gas, measured in joules.

\Delta E - Change in energy, measured in joules.

If we know that Q_{in} = 1.36\times 10^{2}\,J and W_{out} = 3.19\times 10^{2}\,J, the change in energy of the gas is:

\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J

\Delta E = -1.83\times 10^{2}\,J

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

3 0
2 years ago
A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

\Delta p=m\Delta v=m(v_2-v_1)

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

\Delta p=F.\Delta t

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

\Delta p=14*0.06=0.84

The change of momentum of the dart is 0.84 Nw.s

5 0
2 years ago
A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have
Juliette [100K]

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

7 0
2 years ago
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