The answer to this physics question would be 'a thin tungsten filament'. The element in an incandescent light bulb that releases light energy is a thin tungsten filament. All the other choices are not applicable as answers to this question.
A comet speeds up as it approaches the Sun. Which statement about its kinetic energy is correct option is - (1) The comet has no kinetic energy because it is in outer space.
- Large ice and dust-based bodies known as comets circle the Sun. These ancient objects, which are best known for their long, streaming tails, are relics from the solar system's birth 4.6 billion years ago. The majority of comets are located outside of our solar system. Some are found in the Kuiper Belt, a vast disc that extends past Neptune's orbit. These are known as short-period comets. They orbit the Sun in lesser than 200 years.
- The Outermost Layer, the solar system's sphere-shaped outer edge, which is nearly 50 times further from the Sun than the Kuiper Belt, is home to additional comets. Because of how much longer it takes them to orbit the Sun, these are known as long-period comets. The comet with the longest known orbit completes one orbit in excess of 250,000 years.
To know more about comet
brainly.com/question/8705662
#SPJ1
Answer:
The angular speed of rolling ball is 3.23 rad/sec.
Explanation:
Given that,
Radius = 1.95 cm
Speed = 6.30 cm/s
Suppose, we need to find the angular speed of rolling ball
We need to calculate the angular velocity
Using formula of angular velocity
Where, r = radius
= angular velocity
Put the value into the formula
Hence, The angular speed of rolling ball is 3.23 rad/sec.
Answer:
Explanation:
<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em>,</em><em> </em><em>assuming</em><em> </em><em>there</em><em> </em><em>are</em><em> </em><em>no</em><em> </em><em>energy</em><em> </em><em>losses</em><em>.</em>
<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>m</em><em> </em><em>×</em><em> </em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in</em><em> </em><em>v</em><em>^</em><em>2</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>(</em><em> </em><em>26</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>0</em><em>^</em><em>2</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>676</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>743</em><em>.</em><em>6</em><em> </em><em>joules</em>
C- Sigma Waves, This is what my teacher used to get us to remember https://www.youtube.com/watch?v=bjOGNVH3D4Y
