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Fudgin [204]
3 years ago
13

If a string vibrates at the fundamental frequency of 528 Hz and also produces an overtime with a frequency of 1,056 Hz this over

tune is the
Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
I have a hunch that you're not talking about overtime
OR overtune.  I think you're going for overtone .

For a fundamental frequency of 528 Hz,
1,056 Hz is the second harmonic.
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Which is more reliable—using a manual stop watch or using light gates?<br> Explain.
Kitty [74]
Light gates are more reliable. When using a manual stop watch, it is difficult to stop it at an exact time. A light gate is able to detect when an object passes through a 'gate' with the infrared transmitter and receiver. 
7 0
3 years ago
Give a calculate answer to show that the two values (English system and metric system) for the Planck Constant are equivalent.
Nataly_w [17]

Answer:

Given values of Planck Constant are equivalent in English system and metric system.

Explanation:

Value of Planck's constant is given in English system as 4.14 x 10⁻¹⁵eV s.

Converting this in to metric system .

We have 1 eV = 1.6 x 10⁻¹⁹ J

Converting

     4.14 x 10⁻¹⁵eV s = 4.14 x 10⁻¹⁵x 1.6 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ Joule s

So Given values of Planck Constant are equivalent in English system and metric system.

7 0
3 years ago
Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?
Law Incorporation [45]
Yes, his velocity will decrease the further he slides.
7 0
3 years ago
Which of the following is true regarding the speed of earthquake waves?
Levart [38]

Answer:

p waves travel faster than s waves and surface waves

4 0
3 years ago
A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon
Furkat [3]

Answer:

11

Explanation:

According to Boyle's law:

P\times V=constant

Thus,

P_{cylinder}\times V_{cylinder}=n\times P_{balloon}\times V_{balloon}

Where, n is the number of the balloons

From the question, it is given that:

For balloon:

P = 1.2\times 10^5 Pa

V = 0.040 m³

For cylinder:

P = 1.80\times 10^7 Pa

V = 0.0031 m³

So,

1.80\times 10^7\times 0.0031=n\times 1.2\times 10^5\times 0.040

n = 11.625

<u>So, Maximum number of balloons = 11</u>

7 0
3 years ago
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