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Inessa [10]
3 years ago
11

Decide whether the attribute describes Earth, Venus, or both Earth and Venus.

Physics
2 answers:
kykrilka [37]3 years ago
5 0

Answer:

1) Has a rocky, metallic composition -Both

2) Experiences retrograde rotation, spinning clockwise as viewed from above- Venus

3)Experiences the greenhouse effect, which warms the planet - Both

4) Is the densest planet in the solar system - Earth

5) Is located an ideal distance from the Sun, allowing it to support life -Earth

6) Is one of the brightest objects in the night sky, sometimes mistaken for a star-Venus

Explanation:

Venus and Earth are terrestrial planets. They have rocky surface. Venus is characterized by a very thick atmosphere which traps the sun light and makes it the hottest planet of the solar system. Greenhouse effect warms both the planets.

Earth is the only planet on which life exists. It is located at ideal distance from the Sun which helps to maintain sustainable conditions -temperature to support life on it. Venus is known as morning and evening star as it is the brightest objects.

Earth is the densest planet of the solar system having density 5.51 g/cm³. Venus experiences retrograde rotation due to the tilt of its axis (177.3°). Due to this tilt it appears to rotate in opposite direction than other planets.

masha68 [24]3 years ago
3 0

1). both

2). Venus

3). Venus catastrophically; Earth too but much less.

4). Earth

5). Earth

6). Venus (It would be pretty hard for US to mistake Earth for a star.)


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lutik1710 [3]

Answer:

speed of electrons = 3.25 × 10^{7} m/s

acceleration in term g is 3.9 × 10^{17} g.

radius of circular orbit is 2.76 × 10^{-4} m

Explanation:

given data

voltage = 3 kV

magnetic field = 0.66 T

solution

law of conservation of energy

PE = KE

qV = 0.5 × m × v²

v = \sqrt{\frac{2qV}{m}}

v = \sqrt{\frac{2\times 1.6 \times 10^{-19}\times 3}{9.1\times 10^{-31}}

v = 3.25 × 10^{7} m/s

and

magnetic force on particle movie in magnetic field

F = Bqv

ma = Bqv

a = \frac{Bqv}{m}  

a =  \frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}

a = 3.82 × 10^{18} m/s²

and acceleration in term g

a = \frac{3.82\times 10^{18}}{9.81}  

a = 3.9 × 10^{17} g

acceleration in term g is 3.9 × 10^{17} g.

and

electron moving in circular orbit has centripetal force

F = \frac{mv^2}{r}  

Bqv = \frac{mv^2}{r}  

r = \frac{mv}{Bq}  

r = \frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}  

r = 2.76 × 10^{-4} m

radius of circular orbit is 2.76 × 10^{-4} m

8 0
3 years ago
An astronaut is standing on the surface of a planetary satellite that has a radius of 1.74 × 10^6 m and a mass of 7.35 × 10^22 k
ExtremeBDS [4]

Answer:

2.87 km/s

Explanation:

radius of planet, R = 1.74 x 10^6 m

Mass of planet, M = 7.35 x 10^22 kg

height, h = 2.55 x 10^6 m

G = 6.67 x 106-11 Nm^2/kg^2

Use teh formula for acceleration due to gravity

g=\frac{GM}{R^{2}}

g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.74^{2}\times 10^{12}}

g = 1.62 m/s^2

initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0

Use third equation of motion

v^{2}=u^{2}-2gh

0 = v² - 2 x 1.62 x 2.55 x 10^6

v² = 8262000

v = 2874.37 m/s

v = 2.87 km/s

Thus, the initial speed should be 2.87 km/s.

6 0
3 years ago
Where can you find the neutrons of an atom? in the nucleus with the protons orbiting the nucleus In the nucleus with the electro
cricket20 [7]

Answer:

Nuclease is the answer I know

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3 0
3 years ago
Find the volume of a sphere of radius 10 mm.
vredina [299]

Answer:

Explanation: This is done using the equation:

\frac{4}{3} π R^{3}

Because the Radius is a know value. We have the following.

\frac{4}{3} π (10mm)^{3}

Which is:

4188.7902 mm

5 0
3 years ago
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Korvikt [17]

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Explanation:

Hope this helps ( not copied and pasted, this answer was done by me so I don't know if it's good or not)

5 0
3 years ago
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