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2 years ago

Rewrite this measurement with a simpler unit, if possible. 4.5·m2m2m

Chemistry

1 answer:

stepladder [879]2 years ago

4 0

Answer:

why are people s opinions and prejudices her greatest obstacles

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If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--> 4 2He+1 0N) , the resulting helium has a mass of 0.993 k

enot [183]

Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H

)−m
He

−m
n

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g

=500
N=500N
A

=3.01×10
26

Energy released =
2
N

×5.95×10
−13
J
=8.95×10
13

6 0

2 years ago

A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio

myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

$W = -P*(V_{2} - V_{1})$

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K); R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

$V_{1}$ is the initial volume = 0.350 L

$V_{2}$ is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*( $V_{2}$ - 0.350) L

$V_{2}$ = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

7 0

3 years ago

Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base

Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

$\frac{r_{cation}}{r_{anion}}$

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation, $Na^+$ = 102 pm

Radius of cation, $Br^-$ = 196 pm

$\frac{r_{cation}}{r_{anion}}=\frac{102}{196}=0.520$

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.

8 0

3 years ago

Water interacts with polar substances like –OH groups but not with non-polar substances like methyl (-CH3) or ethyl groups (-CH2

Otrada [13]

To answer this, we look at the polarities of these molecules given. A molecule is said to be polar when there is an unequal shraing of electrons the opposite is called nonpolar.
CH4 = nonpolar
CH3OH = polar
CH3 CH3 = nonpolar
CH3 CH2 CH2 OH = polar
<span>CH3 CH2 CH2 CH2 CH2 CH3 = nonpolar</span>

3 0

2 years ago

Ce presiune au 40L gaz la temperatura de 100⁰C, dacă la presiunea de 6 atm și temperatura de 50⁰C volumul ocupat este de 20L.

sammy [17]

Answer:

3,46 atm

Explanation:

Tenemos;

P1 =?

T1 = 100 + 273 = 373 K

V1 = 40 litros

P2 = 6 atmósferas

T2 = 50 + 273 = 323 K

V2 = 20 litros

Desde;

P1V1 / T1 = P2V2 / T2

P1V1T2 = P2V2T1

P1 = P2V2T1 / V1T2

P1 = 6 * 20 * 373/40 * 323

P1 = 44760/12920

P1 = 3,46 atm

5 0

3 years ago