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2 years ago

Is an ocean wave electromagnetic or mechanical

Physics

1 answer:

swat322 years ago

3 0

Answer:

mechanical

Explanation:

the energy is carried by water <3 hope this helped

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Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.

-BARSIC- [3]

The total resistance in a series circuit is equal to the sum of all resistors (R total = ΣRi).

R total = R1 + R2 + R3 = (3 + 4 + 5) Ω = 12 Ω

5 0

3 years ago

radio waves travel at the speed of light, 3 x 10^8 m/s. the wavelength of a radio wave record is 200,000,000 hz is?

ludmilkaskok [199]

Answer:

1.5m

Explanation:

Speed of waves is given as the product of the wavelength and frequency. Sometimes when frequency is not given but the period is given, we get the frequency as the reciprocal of the period. The speed of waves is given in m/s, wavelength in m while frequency in Hz.

Speed, s= fw and making w the subject of formula,

$w=\frac {s}{f}$

Substituting 300, 000, 000 m/s for s and 200, 000, 000 for f then we obtain that

$w=\frac {300000000}{200000000}=1.5 m$

6 0

3 years ago

A certain gasoline engine has an efficiency of 35.3%. What would the hot reservoir temperature be for a Carnot engine having tha

levacccp [35]

Answer:

The temperature of hot reservoir is 669.24 K.

Explanation:

It is given that,

Efficiency of gasoline engine, $\eta=35.3\%=0.353$

Temperature of cold reservoir, $T_C=160^{\circ}C=433\ K$

We need to find the temperature of hot reservoir. The efficiency of Carnot engine is given by :

$\eta=1-\dfrac{T_C}{T_H}$

$T_H=\dfrac{T_C}{1-\eta}$

$T_H=\dfrac{433}{1-0.353}$

$T_H=669.24\ K$

So, the temperature of hot reservoir is 669.24 K. Hence, this is the required solution.

4 0

3 years ago

A ball thrown horizontally from the top of a building hits the ground in 0.600 s. If it had been thrown with twice the speed in

ludmilkaskok [199]

Answer:

none of the answers is correct, the time is the same t₁ = t₂ = 0.600 s

Explanation:

This is a kinematics exercise, analyze the situation a bit. The vertical speed in both cases is the same is zero, the horizontal speed in the second case is double (vₓ₂ = 2 vₓ₁)

let's find the time to hit the ground

y = y₀ + I go t - ½ g t²

0 = y₀ - ½ g t²

t = √ 2y₀ / g

with the data from the first launch

y₀i = ½ g t²

y₀ = ½ 9.8 0.6²

y₀ = 1,764 m

with this is the same height the time to descend in the second case is the same

t₂ = 0.600 s

this is because the horizontal velocity change changes the offset on the x axis, but does not affect the offset on the y axis

Therefore, none of the answers is correct, the time is the same

t₁ = t₂ = 0.600 s

5 0

3 years ago

6th grade science I mark as brainliest.

Viktor [21]

Answer:

divide 10 by 50.

Explanation:

Because its time over speed 10/50

7 0

2 years ago

Read 2 more answers