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Ahat [919]
3 years ago
6

A box weighing 18 N requires a force of 6.0 N to drag it at a constant rate. What is the coefficient of sliding friction?

Physics
2 answers:
Rzqust [24]3 years ago
6 0
0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18
kolezko [41]3 years ago
3 0

Answer:

Coefficient of sliding friction is 0.33.

Explanation:

The force of sliding friction is proportional to the normal force. It is given by:

F_s=\mu _sF_N

The normal force of the box is equal to its weight as the force in the vertical direction is balanced.

F_N= 18N

F_s= 6.0N (given)

Thus, the coefficient of sliding friction is:

\mu _s=\frac{F_s}{F_N}=\frac{6.0}{18} = 0.33

Thus, the coefficient of sliding friction is 0.33.

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