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Tju [1.3M]
4 years ago
7

3. According to Hund's rule, what's the expected magnetic behavior of vanadium (V)?

Physics
1 answer:
ivanzaharov [21]4 years ago
6 0

Answer:

Diamagnetic

Explanation:

Hunds rule states that electrons occupy each orbital singly first before pairing takes place in degenerate orbitals. This implies that the most stable arrangement of electrons in an orbital is one in which there is the greatest number of parallel spins(unpaired electrons).

For vanadium V ion, there are 18 electrons which will be arranged as follows;

1s2 2s2 2p6 3s2 3p6.

All the electrons present are spin paired hence the ion is expected to be diamagnetic.

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Answer: 0.66 V

Explanation:

Given

Magnetic field, B = 0.963 T

Instantaneous rare = 74.5 cm/s = 0.745 m/s

radius, r = 14.7 cm = 0.147 m

We will use the formula

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emf = d(Bπr²)/dt

if B is constant, then we can say

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emf = 2πrB dr/dt substituting each values, we have

emf = 2 * 3.142 * 0.147 * 0.963 * 0.745

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A 4.8-kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t=0 s, the blo
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Answer:

E) 80 N/m

Explanation:

Given;

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From Newton's second law of motion;

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Also, from Hook's law;

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