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3 years ago

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a liquid with a specific heat of 1900J/Kg° C has 4750 joules of heat energy is added to it. if the temperature increases from 20

° to 30°, what is the mass of the liquid

1 answer:

GREYUIT [131]3 years ago

8 0

E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values we get :
</span> $\frac{4750}{1900*10}$
<span>
solving it we get the answer that is 0.25kg or 250 grams

</span>

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