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amid [387]
2 years ago
11

a liquid with a specific heat of 1900J/Kg° C has 4750 joules of heat energy is added to it. if the temperature increases from 20

° to 30°, what is the mass of the liquid
Physics
1 answer:
GREYUIT [131]2 years ago
8 0
E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values  we get :
</span>\frac{4750}{1900*10}
<span>
solving it we get the answer that is 0.25kg or 250 grams

</span>
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Answer:

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2 years ago
In the lesson a thermos is presented as an example of an isolated energy system. How could you change the thermos into an open e
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A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic
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Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light c= 2.99793\times10^{8}\ m/s

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}

Put the value into the formula

\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}

\Delta l=1\sqrt{1-(0.96)^2}

\Delta l=0.28\ m

We need to calculate the time the stick take to move

Using formula of time

t=\dfrac{\Delta l}{v}

Put the value into the formula

t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}

t=9.72\times10^{-10}\ sec

t=0.97\ ns

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0
2 years ago
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anyanavicka [17]
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3 years ago
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A 2.5 m -long wire carries a current of 8.0 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
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Answer:

Explanation:

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Part A

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Part B

y component of B = 0

Part C

z component of B = .115 T .

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