A horizontal force of 200N is applied to a 55kg cart across a 10m level surface. If the cart accelerates at 2.0m/s^2, then what
2 answers:
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Yes, the ions can exit slit P without being deflected, if the electric field strength is 170.6 N/C
Explanation:
When the ions are inside the container, they are subjected to two forces, with directions opposite to each other:
- The force due to the electric field, whose magnitude is
, where q is the charge of the ion and E is the strength of the electric field
- The force due to the magnetic field, whose magnitude is
, where v is the speed of the ions and B is the strength of the magnetic field
The ions will move straight and undeflected if the two forces are equal and opposite. By using Fleming Left Hand rule, we notice that the magnetic force on the (negative) ions point upward: this means that the electric field must be also upward (so that the electric force on the ions is downward). Then, the two forces are balanced if
which translates into
Therefore, if the speed of the ions is equal to this ratio, the ions will go undeflected.
We can even calculate the value of E at which this occurs. In fact, we know that the ions are earlier accelerated by a potential difference , so we have that their kinetic energy is given by the change in electric potential energy:
where
Solving for v, the speed,
And since the magnetic field strength is
B = 0.83 T
The strength of the electric field must be
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Answer:
total energy is 14.12kj
energy at 85% is 12kJ
Explanation:
