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anyanavicka [17]
3 years ago
15

The dimensions of the disk of our milky way galaxy are:.

Physics
1 answer:
Katen [24]3 years ago
6 0

Answer:

According to studies, the milky way is approximately, "170,000–200,000 light-years (52–61 kpc) in diameter and, on average, approximately 1,000 ly (0.3 kpc) thick."

With that being said, it is safe to say that the dimensions are somewhere around 100,000 by 1,000

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Why is moon is non-lomis back​
qwelly [4]

Explanation:

At night, when that part of Earth is facing away from the sun, space looks black because there 8s no nearby bright source of light like the sun , to be scattered

4 0
4 years ago
This triangle is an isosceles right triangle. This means that the triangle contains a _____ angle and _______ sides.
Svetlanka [38]

Answer:

There is a right angle and it has three sides.

Explanation:

There are two 45 degree angles and since a triangles sides ALWAYS add up to 180 we know the the other side has to be 90 degrees because 45+45+90=180. And we know that every triangle has three sides because "tri" means three.

3 0
2 years ago
Read 2 more answers
A ball is dropped off the side of a bridge,<br> After 1.55 S, how far has it fallen?<br> (Unit=m)
kow [346]

Answer:

Distance S = 11.77 m (Approx.)

Explanation:

Given:

Time t = 1.55 Second

Gravity acceleration = 9.8 m/s²

Find:

Distance S

Computation:

S = ut + (1/2)(g)(t)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

Distance S = 11.77 m (Approx.)

7 0
3 years ago
A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

5 0
3 years ago
A paved blacktop parking lot was built on what was
USPshnik [31]

Answer:

The answer is B. less permeability.

Explanation:

5 0
3 years ago
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