The dimensions of the disk of our milky way galaxy are:.

Physics

1 answer:

Katen [24]2 years ago

6 0

Answer:

According to studies, the milky way is approximately, "170,000–200,000 light-years (52–61 kpc) in diameter and, on average, approximately 1,000 ly (0.3 kpc) thick."

With that being said, it is safe to say that the dimensions are somewhere around 100,000 by 1,000

You might be interested in

What do you mean by resistance of conductor?state it’s unit.

dalvyx [7]

Answer:

its unit is Ohm

Explanation:

Resistance means material which resist the passing current through it and the value of resistance says how much the material is resisting the current and it temperature dependent and the unit is Ohm.

7 0

3 years ago

If you need 40.0 Nm of torque in order to loosen a nut on a wn

KonstantinChe [14]

Answer:

0.301 m

Explanation:

Torque = Force × Radius

τ = Fr

40.0 Nm = 133 N × r

r = 0.301 m

The mechanic must apply the force 0.301 m from the nut.

6 0

3 years ago

Conduction is the movement of heat energy because of

Ira Lisetskai [31]

Answer:

Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them. This then continues and passes the energy from the hot end down to the colder end of the substance.

Explanation:

pls make me brainliest

6 0

2 years ago

Read 2 more answers

If you're studying the science of sound, you're studying____?

timurjin [86]

The study of sound is called sonics and the study of sound waves are acoustics

3 0

3 years ago

Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2

jek_recluse [69]

The orbital radius is: $r=\frac{GM}{v^2}$

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

$\frac{GMm}{r^2}=m\frac{v^2}{r}$