For an object to appear blue, what must the object do to blue light waves?

A caris initially at rest starts moving with a constant acceleration of 0.5 m/s2 and travels a distance of 5 m. Find

EleoNora [17]

Answer:

(I)

${ \bf{ {v}^{2} = {u}^{2} - 2as }} \\ {v}^{2} = {0}^{2} - (2 \times 0.5 \times 5) \\ {v}^{2} = 5 \\ { \tt{final \: velocity = 2.24 \: {ms}^{ - 1} }}$

(ii)

${ \bf{v = u + at}} \\ 2.24 = 0 + (0.5t) \\ { \tt{time = 4.48 \: seconds}}$

8 0

3 years ago

The energy due to Earth pulling down on an object is called ___.

Slav-nsk [51]

Gravity is the energy due to Earth pulling down on an object.

6 0

3 years ago

What is all cells in a body that arent formed in a reproductive organ???

vovangra [49]

Explanation:

An organ is made of several types of tissue and therefore several types of cells. For example, the heart contains muscle tissue that contracts to pump blood, fibrous tissue that makes up the heart valves, and special cells that maintain the rate and rhythm of heartbeats.

3 0

2 years ago

A block of aluminium of density 7900 kg/m3 has a volume of 250 cm. Find the<br>mass of the block.

pashok25 [27]

Answer:

mass of block=2.7 gm

Explanation:

concept: Density=mass/volume

given:ρ=2700 kg/m^3 and v=250 cm^3 (in cm^3 not in m^3)

=> v= convert cm^3 to m^3

there fore= 1 cm^3=1 cm*1 cm*1 cm

i.e 1 cm^3=1/100*1/00*1/100 m^3 => 1 cm^3=1/1000000 m^3

ρ=m/v

=>mass=ρ*volume

=>mass=2700*1/10^-6

=>mass=2.7*10^-3 kg =>2.7 gm

8 0

2 years ago

Calculate the equivalent resistance for both circuits. Series circuit: 2 Ω and 4 Ω Parallel circuit: 2 Ω and 4 Ω Which circuit h

goldenfox [79]

Equivalent resistance is also known as the overall resistance.

For resistors in a series circuit, the total resistance is computed using the formula:

$R_{T} = R_{1}+ R_{2}+ R_{3}... R_{n}$

In other words, you just add up the resistance of each resistor in the series circuit. In your case you only have two resistors. You have 2Ω and 4Ω. So all you need to do is add that up.

$R_{T} = R_{1}+ R_{2}$
$R_{T} = 2 + 4=6$

The total resistance of the series circuit is 6Ω

In a parallel circuit you get the total resistance using the formula:
$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}...+\frac{1}{R_{n}}$

First you get the sum of all fractions and at the end take the reciprocal of the resulting fraction and divide. So let us take your problem into consideration where you have two resistors that have a resistance of 2Ω and 4Ω.

$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}$
$\frac{1}{R_{T}} = \frac{1}{2}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{2}{4}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{3}{4}$

Get the reciprocal of the resulting fraction 3/4 and then divide. The reciprocal of 3/4 is 4/3.

4/3 = 1. 33Ω

So if you compare the equivalent resistance of the two circuits, the series circuit has a higher equivalent resistance.

3 0

3 years ago

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