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inessss [21]
3 years ago
5

Time time it takes two successive crests of an ocean wave to pass a given point is called

Physics
1 answer:
-Dominant- [34]3 years ago
6 0

The question is asking for "time".

Even if you didn't know anything about waves, you could look down this list and see that 'peak', 'amplitude', and 'frequency' are not times, so none of those can be the answer to the question.  It must be <em>"period"</em>.

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Plz help will give brainlest! if you cant help, well, merry christmas!
soldi70 [24.7K]

most fossils are found in sedimentary rocks

8 0
2 years ago
A 450g mass on a spring is oscillating at 1.2Hz. The totalenergy of the oscillation is 0.51J. What is the amplitude.
Volgvan

Answer:

A=0.199

Explanation:

We are given that  

Mass of spring=m=450 g==\frac{450}{1000}=0.45 kg

Where 1 kg=1000 g

Frequency of oscillation=\nu=1.2Hz

Total energy of the oscillation=0.51 J

We have to find the amplitude of oscillations.

Energy of oscillator=E=\frac{1}{2}m\omega^2A^2

Where \omega=2\pi\nu=Angular frequency

A=Amplitude

\pi=\frac{22}{7}

Using the formula

0.51=\frac{1}{2}\times 0.45(2\times \frac{22}{7}\times 1.2)^2A^2

A^2=\frac{2\times 0.51}{0.45\times (2\times \frac{22}{7}\times 1.2)^2}=0.0398

A=\sqrt{0.0398}=0.199

Hence, the amplitude of oscillation=A=0.199

4 0
3 years ago
Two uniform spheres,each of mass 0.260kg are fixed at points A and B
Ivan

Answer:

a) 2.76x10^-9 m/s^2

b) downward

Explanation:

a) In order to do this, we need to use the newton's law of gravitation which is:

F = G.m/r²

Where:

G: Constant of gravitation (6.67x10^-11 N/m)

m: mass of the object

r: distance or radius of the object.

In this case, we have two spheres, so this law becomes:

F = G*m1*m2 / r²

Now, you are not providing a picture with this, however, this problem is very similar to one I solved before, so, I'm gonna use the same values to solve this. If, you have different values for the distance, just replace them in this procedure and should get the correct and more accurate answer.

In this case, the distance that separates sphere in P from sphere A and B is 10 cm. As both spheres have the same mass and they are at the same distance from P, we can assume that F1 = F2 so:

F1 = (6.67x10^-11) * (0.01) * (0.26) / (0.1)² = 1.73x10^-11 N

sphere at P, will roll downward to the middle of sphere A and B. The distance between these two points it's 8 cm (See picture attached)

Now, according to my data, they are exerting a force in the y axis, so:

F1y = Fy * senФ

senФ using trigonometry is:

senФ = opposite lenght / hipotenuse

senФ = 8/10 = 0.8

Replacing:

F1y = 1.73x10^-11 * 0.8 = 1.38x10^-11 N

This force it's exactly the same as F2y, so the total force is:

F = 1.38x10^-11 * 2 = 2.76x10^-11 N

Finally, using the second law of Newton:

F = m*a

Solving for a:

a = F/m

replacing:

a = 2.76x10^-11 / 0.01

a = 2.76x10^-9 m/s²

According to the picture and the value of this magnitude, it's going downward.

3 0
3 years ago
When the same force id applied to a smaller area, the pressure is A. Lower B.greater C. Reduced D. The same
irakobra [83]
I believe the correct answer is "B. Greater".
7 0
3 years ago
The affinity of hemoglobin for oxygen is ________ as the partial pressure of oxygen is raised.
san4es73 [151]

The affinity of hemoglobin for oxygen is <u>increased</u> as the partial pressure of oxygen is raised.

Hemoglobin is the most vital constituent of red blood cells.

It is a kind of protein found in red blood cells that transfers oxygen to all parts of your body.

Hemoglobin is made up of proteins called 'heme' to which oxygen molecules become attached and travel throughout the body.

The blood carrying oxygen is called oxygenated blood and when it reaches the lungs, oxygen molecules detach and brings carbon dioxide along to remove it from the body through respiration.

If you need to learn more about hemoglobin click here:

brainly.com/question/10122738

#SPJ4

3 0
1 year ago
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