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Arlecino [84]
2 years ago
9

A(n) 15.9 kg rock is on the edge of a(n

Physics
1 answer:
Mariulka [41]2 years ago
5 0

The potential energy (P.E) of the rock relative to the base of the cliff is 31,054.926 Joules..

<u>Given the following data:</u>

  • Mass of rock = 7.5 kg
  • Height = 0.7 m
  • Acceleration due to gravity = 9.8 m/s^2

To calculate the potential energy (P.E) of the rock relative to the base of the cliff:

<h3>What is potential energy?</h3>

Potential energy (P.E) can be defined as the energy that is possessed by an object due to its position (height) above planet Earth.

Mathematically, potential energy (P.E) is given by this formula;

P.E = mgh

<u>Where:</u>

  • P.E is the potential energy.
  • m is the mass of an object.
  • g is the acceleration due to gravity.
  • h is the height of an object.

Substituting the given parameters into the formula, we have;

P.E = 15.9 \times 9.8 \times 199.3

P.E = 31,054.926 Joules.

Read more on potential energy here: brainly.com/question/8664733

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Approximately how much air is in a column 1-cm2 in cross section that extends from sea level to the top of the atmosphere?
laila [671]

Approximately 101 N air is in a column 1-cm2 in cross-section that extends from sea level to the top of the atmosphere

The basic level for determining height and depth on Earth is the sea level. The ocean's surface tends to seek the same level since it is one continuous body of water. However, the sea level is never fully level due to winds, currents, river discharges, and changes in gravity and temperature.

At the equator, the radius of the Earth at sea level is 6378.137 km (3963.191 mi). At the poles, it is 6,356.752 km (3,949.903 km), and on average, it is 6,371.001 km (3,958.756 mi). The elevation of the shoreline—the boundary between the ocean and the land—is referred to as sea level. Land that is higher than this altitude is above sea level, and land that is lower is below sea level.

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8 0
2 years ago
An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel
Licemer1 [7]

Answer:

v=4.44\frac{m}{s}

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero)  and accelerates at a constant rate, position can be described like this: x=v_{0}t +\frac{1}{2} at^{2} where x is the position, t is the time a is the acceleration and v_{0} is initial velocity. In this way acceleration can be found. a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }.

Now we are able to found velocity at any time with the formula: v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}

3 0
3 years ago
What wave on the electromagnetic spectrum has the highest frequency?
Jet001 [13]

Answer:

Explanation:

Answer: Gamma rays

Gamma rays have the highest frequency.

What is an electromagnetic wave?

An electromagnetic wave requires no medium for its propagation.

It consists of a spectrum of different wavelengths.

Different wavelengths of rays have different energies and different frequencies.

Higher frequency rays have the highest energies.

What is gamma-ray?

These are ionized radiations.

Gamma radiations are obtained from the decay of the atomic nucleus.

It has the highest frequency which is why it can penetrate through matter.

It has the smallest wavelength and highest energy.

The frequency of gamma rays is more than 10^19 cycles per second and wavelength less than 100 picometers.

6 0
2 years ago
Read 2 more answers
Consider a concave spherical mirr or that has focal length f = +19.5 cm.
lidiya [134]

The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

<h3>What is concave mirror?</h3>

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

<h3>Object distance of the concave mirror</h3>

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

  • f is the focal length of the mirror
  • v is the object distance
  • u is the image distance

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

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7 0
1 year ago
N2O is the chemical formula of a covalent compound used in the production of whipping cream. The elements that
WARRIOR [948]

N₂O: Nitrous oxide

oxygen

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