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3 years ago

A(n) 15.9 kg rock is on the edge of a(n

Physics

1 answer:

Mariulka [41]3 years ago

5 0

The potential energy (P.E) of the rock relative to the base of the cliff is 31,054.926 Joules..

<u>Given the following data:</u>

Mass of rock = 7.5 kg

Height = 0.7 m

Acceleration due to gravity = 9.8 $m/s^2$

To calculate the potential energy (P.E) of the rock relative to the base of the cliff:

<h3>What is potential energy?</h3>

Potential energy (P.E) can be defined as the energy that is possessed by an object due to its position (height) above planet Earth.

Mathematically, potential energy (P.E) is given by this formula;

$P.E = mgh$

<u>Where:</u>

P.E is the potential energy.

m is the mass of an object.

g is the acceleration due to gravity.

h is the height of an object.

Substituting the given parameters into the formula, we have;

$P.E = 15.9 \times 9.8 \times 199.3$

P.E = 31,054.926 Joules.

Read more on potential energy here: brainly.com/question/8664733

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IMPORTANT 3 QUESTIONS!

Brums [2.3K]

Answer:

7. 20,000,000 mL.

8. 8,000 m.

9. 120,000 secs.

10. 4

Explanation:

7. Determination of the volume in millilitres (mL)

Volume in litre (L) = 20,000 L

Volume in millilitres (mL) =..?

The volume in mL can be obtained as follow:

1 L = 1,000 mL

Therefore,

20,000 L = 20,000 x 1,000 = 20,000,000 mL.

Therefore, 20,000 L is equivalent to 20,000,000 mL.

8. Determination of the distance in metre (m)

Distance in mile = 5 mile

Distance in metre =?

First, we shall convert from mile to kilometre.

This can be done as follow:

1 mile = 1.6 km

Therefore,

5 mile = 5 x 1.6 = 8 km

Finally, we shall convert 8 km to metre (m).

This is illustrated below:

1 km = 1,000 m

Therefore,

8 km = 8 x 1,000 = 8,000 m

Therefore, 5 miles is equivalent to 8,000 m.

9. Determination of the time in seconds.

Time = 400 minutes for 5 days.

First, we shall convert 400 mins to hour.

This is illustrated below:

60 minutes = 1 hour

Therefore,

400 mins = 400/60 = 20/3 hours

The time (hours) is 20/3 hours in 1 day.

Therefore, the time (hours) in 5 days will be = 20/3 x 5 = 100/3 hours.

Next, we shall convert 100/3 hours to minutes.

This is illustrated below:

1 hour = 60 minutes

Therefore,

100/3 hours = 100/3 x 60 = 2000 mins

Finally, we shall convert 2000 mins to seconds.

This is illustrated below:

1 mins = 60 secs

2000 mins = 2000 x 60 = 120,000 secs.

Therefore, the time is 120,000 secs.

10. Determination of the number of significant figures.

To obtain the significant figures of a number, we simply count all the numbers available.

Therefore, the number of significant figures for 9876 is 4.

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4 years ago

Which statement is a scientific theory?

Dmitry [639]

Answer:

I think it is D

Explanation:

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3 years ago

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If the temperature of the conductor is increased, the electrons’ speeds decrease

Tatiana [17]

Answer:

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Explanation:

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3 years ago

The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s. (a) What

Neko [114]

Complete Question

The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s.

(a) What is its angular acceleration in revolutions per minute-squared

(b) How many revolutions does the engine make during this 20 s interval?

rev

Answer:

$\alpha = 6261 \ rev/minutes^2$

$\theta = 613 \ revolutions$

Explanation:

From the question we are told that

The initial angular speed is $w_i = 1120 \ rev/minutes$

The angular speed after $t = 13.8 s = \frac{13.8}{60 } = 0.23 \ minutes$ is $w_f = 2560 \ rev/minutes$

The time for revolution considered is $t_r = 20 \ s = \frac{20}{60} = 0.333 \ minutes$

Generally the angular acceleration is mathematically represented as

$\alpha = \frac{w_f - w_i }{t}$

=> $\alpha = \frac{2560 - 1120 }{0.23}$

=> $\alpha = 6261 \ rev/minutes^2$

Generally the number of revolution made is $t_r = 20 \ s = \frac{20}{60} = 0.333 \ minutes$ is mathematically represented as

$\theta = \frac{1}{2} * (w_i + w_f)* t$

=> $\theta = \frac{1}{2} * (1120+ 2560 )* 0.333$

=> $\theta = 613 \ revolutions$

5 0

3 years ago

I’m stuck on this problem, help is very appreciated!!

yaroslaw [1]

Explanation:

Use the equation F=m×a

F= 1500 N

M= 500kg

a= F/M

a= 1500÷ 500

a= 3m/s^2

8 0

3 years ago

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