Answer:
v
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One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.Nov 23, 2016
Explanation:
To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

Where
V = Velocity
A = Cross-sectional Area
Our values are given as



Since there is continuity we have now that,






Therefore the speed of the water's house supply line is 0.347m/s
Answer
given,
radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m
mass of electron, M = 9.11 x 10⁻³¹ Kg
charge of electron, q₁ = 1.6 x 10⁻¹⁹ C
q₂ = 1.6 x 10⁻¹⁹ C
we know, force between two charges


F = 8.20 x 10⁻⁸ N
b) using newton's second law
F = m a
m a = 8.20 x 10⁻⁸

a = 9 x 10²² m/s²
c) speed of the electron


v² = 4.77 x 10¹²
v = 2.18 x 10⁶ m/s
d) the period of the circular motion.



T = 1.53 x 10⁻¹⁶ s
The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
<h3>Volume of molybdenum</h3>
V = (zm/ρN)
where;
- z is 2 for cubic unit cell
- m is mass of the molybdenum
- ρ is density of the molybdenum
V = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
<h3>Edge length of the unit cell</h3>
a³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
Learn more about edge length here:
brainly.com/question/16673486
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