Answer:
FA / FB = 100
Explanation:
given two identical cars
let their initial speed be U m/s
for car 1 let it deaccelerates with a1
0 = U² - 2*a1*(10cm)
a1 = U² / (2*(0.1))
car2 deaccelerates with a2
0 = U² - 2*a2*(10)
a2 = U² / (2*(10))
FA = m*a1
FB = m*a2
FA/FB = a1 / a2
= 10/0.1
= 100
FA/FB = 100
Answer:
4 m/s.
Explanation:
The following data were obtained from the question:
Distance travalled (d) = 20 m
Time (t) = 5 secs
Speed (S) =?
Speed is defined as the rate of change of distance moved with time. Mathematically, it is expressed as:
Speed (S) = Distance (d) /time (t)
S = d/t
With the above formula, we can easily calculate the speed of the individual as follow:
Distance travalled (d) = 20 m
Time (t) = 5 secs
Speed (S) =?
S = d/t
S = 20/5
S = 4 m/s
Therefore, the speed of the individual is 4 m/s
Answer:
30000 J = 30 kJ
Explanation:
Kinetic energy is the energy possessed by a moving object solely due to its motion.
You can get the K.E. of an object using the equation,
K.E. =
So you get,
K.E. =
= 30000 J = 30 kJ
Concept:
Frequency- It is defined as the number of oscillations occur in one second.
Its SI unit is Hertz (Hz)
Given: Produced sound vibrations is 18,500 cycles in 0.75 seconds
∵ In 0.75 second, produced sound has oscillations = 18,500 cycles
∴ In 1.0 second, produced sound has oscillations = (18,500 ÷ 0.75) Hz
The frequency of the sound will be ≈ 24,667 Hz
From the study of the given graph, only the animals (c) Cats, (b) Moths and (a) Bats can hear the produced sound because their upper audible frequency range is greater than 24,667 Hz.
Answer:
0.75 second
Explanation:
The equation is
Let t be the time when it is at 73 feet. Substitute, h = 73 in the above equation and then find the value of t.
Take positive sign
t = 0.75 second