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Anna71 [15]
3 years ago
7

If a motorcycle covers 5km in 10 minutes , how far does it move in 1 second ?​

Physics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

A motorcycle moves 5km in 10 minutes(10×60s=600 seconds)

A motorcycle moves 5/600 km in 1 second.

A motorcycle moves 1/120 km in 1 second.( 5/600 = 1/120)

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Autorhythmic cells can generate action potentials spontaneously because they have Autorhythmic cells can generate action potenti
OlgaM077 [116]

Answer:

They can generate potentials spontaneously because they have Unstable Membrane Potentials.

Explanation:

Autorythmic cells or Pacemaker cells are cells that provide Action potentials (electrical impulses) that starts off the cardiac cycle.

N:B This action potential is created spontaneously.

To explain further, the heart originate in specialized cardiac muscle cells, called autorhythmic cells, that can excite themselves and therefore are able to generate an action potential without external stimulation by nerve cells. And this sets the cardiac cycle i

(Pumping of the heart) into motion. (The pace maker potential)

The Autorhythmic cells create an action potential spontaneously

And this is possible because they have an UNSTABLE RESTING POTENTIAL that is continuously depolarizing, while it drifts slowly toward threshold. As Na+ ions enter the cell, the inner surface of the plasma membrane becomes less negative gradually, thus generating the pacemaker potential.

8 0
3 years ago
Read 2 more answers
One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor
Bess [88]

Answer:

a) The final velocity is 20 m/s when the large-mass object is the one moving initially.

b) The final velocity is 9.0 m/s when the small-mass object is the one moving initially.

Explanation:

The momentum of the system is calculated as the sum of the momenta of each object. Each momentum is calculated as follows:

p = m · v

Where:

p =  momentum.

m =  mass.

v = velocity.

Then, the momentum of the system is the following:

m1 · v1 + m2 · v2 = (m1 + m2) · v

Where:

m1 = mass of the bigger object.

v1 = velocity of the bigger object.

m2 = mass of the smaller object.

v2 = velocity of the smaller object.

v = final velocity of the two objects after the collision.

Solving the equation for the final velocity:

(m1 · v1 + m2 · v2)/ (m1 + m2) = v

a) Let´s calculate the final velocity when the bigger object is moving:

(7.1 kg · 29 m/s + 3.2 kg · 0)/(7.1 kg + 3.2 kg) = v

<u>v = 20 m/s</u>

b) When the smaller object is moving:

(7.1 kg · 0 m/s + 3.2 kg · 29 m/s) / (7.1 kg + 3.2 kg) = v

<u>v = 9.0 m/s</u>

7 0
3 years ago
When you lift an object, you add the energy of lifting to the object.<br> Tor F
PtichkaEL [24]

It's true, when we lift an object we add energy to it.

because, when we lift an object by applying force , the object attains a height and hence the energy gets stored in it, in the form gravitational potential energy .

6 0
3 years ago
What happens to the iron in the coilgun if the electricity in the coil was turned on
Andrews [41]

  • <em><u>The piece of iron has become a magnet. Some substances can be magnetized by an electric current. When electricity runs through a coil of wire, it produces a magnetic field. The field around the coil will disappear, however, as soon as the electric current is turned off.</u></em>
7 0
2 years ago
Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.
Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

Q_1 = Q_2

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

Q = VA

Where

V = Velocity

A = Cross-sectional Area

Our values are given as

Q_2 = 1.2*10^{-4}m^3/s

d = 0.021m

r = \frac{0.021}{2} = 0.0105m

Since there is continuity we have now that,

V_1A_1 = Q_2

V_1A_1 = 1.2*10^{-4}

V_1 = \frac{1.2*10^{-4}}{A_2}

V_1 = \frac{1.2*10^{-4}}{\pi r^2}

V_1 = \frac{1.2*10^{-4}}{\pi (0.0105)^2}

V_1 =0.347m/s

Therefore the speed of the water's house supply line is 0.347m/s

7 0
3 years ago
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