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Anna71 [15]
3 years ago
7

If a motorcycle covers 5km in 10 minutes , how far does it move in 1 second ?​

Physics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

A motorcycle moves 5km in 10 minutes(10×60s=600 seconds)

A motorcycle moves 5/600 km in 1 second.

A motorcycle moves 1/120 km in 1 second.( 5/600 = 1/120)

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A sprinter is running the 100 meter dash at a speed of 24 m/s. How long does it the sprinter to finish?
DerKrebs [107]

Answer:

4.1666666 seconds

Explanation:

100 divided by 24 will give you about 4.1666666 seconds or 4 1/6 seconds. Hope it helps!

6 0
3 years ago
What are the various types of technologies used for exploring space and understanding space
fgiga [73]

The answer is flight technology, satelite technology, and  exploration technology.

The flight technology include advances in jet propulsion and navigation. Satelite have become more and more powerful and hecne communication with distant objects is increasing in efficiency. The emergence of AI robots in space exploration are reducing risks to humans in these deep ventures.  

7 0
3 years ago
Two parallel plate capacitors 1 and 2 are identical except that capacitor 1 has charge +q on one plate and charge −q on the othe
Grace [21]

Answer:

a) the capacitance is the same for both capacitors.

b) The potential difference between the plates for the capacitor with charge +2q, is double of the one for the capacitor  with charge +q.

c) The electric field magnitude between the plates for the capacitor with charge +2q, is double of the one for the capacitor with charge +q

d) The energy stored between the plates for the capacitor with charge +2q, is 4 times the value for the one with charge +q  

Explanation:

a) The capacitance of a capacitor, by definition, is as follows:

C = \frac{q}{V}

Appying Gauss' Law to one of plates, it can be showed, that the capacitance (for a parallel plates capacitor) can be  expressed as follows:

C = ε*A / d

As it can be seen, it does not depend on the charge. so we conclude that the capacitance must be the same for both capacitors, due to they are identical except for the value of the charge on the plates.

b) By definition, as we said above, the capacitance is equal to the proportion between the charge of one of the plates, and the potential difference between them.

If this proportion must remain the same, and one of the capacitors has the double of  the charge than the other, the potential difference must be the double also.

c) Applying Gauss' law, to the surface of one of  the plates, and assuming a constant surface charge density σ, it can be  showed that the  electric field can be calculated as follows:

E*A = Q/ε₀ as σ=Q/A

⇒ E = σ/ε₀

As σ is directly proportional to the charge (being the area A the same), we conclude that the electric field for the capacitor with charge +2q must be the double than the one for the capacitior with charge +q.

c) The electric potential energy, stored between plates of a capacitor, can be written as follows:

Ue = \frac{1}{2} *\frac{q^{2}}{C}

If the capacitance remains the same, we can conclude that the electric potential energy for the capacitor with charge +2q, as the charge is raised to the 2nd power, must be 4 times the one for the capacitor with charge +q.

4 0
3 years ago
What is the kinetic energy of a 7.56 kg bowling ball that is rolling at a speed of 2 m/s ?
postnew [5]

Answer:

K.E=?

Mass=7.56 kg

Velocity=2m/s

Solution::

K.E = 1/2mv^2

K.E=0.5*7.56*(2)^2

K.E= 0.5*7.56*4

K.E=15.12 joules.

7 0
3 years ago
A 332 kg mako shark is moving in the positive direction at a constant velocity of 2.30 m/s along the bottom of a sea when it enc
Digiron [165]

To solve this problem we will apply the concepts related to the conservation of momentum. By definition we know that the initial moment must be equivalent to the final moment of the two objects therefore

p_1 = p_2

m_1u_1+m_2u_2 = m_1v_1+ m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2}= Final velocity of each object

Since the initial velocity relative to the metal tank is at rest, that velocity will be zero. And considering that in the end, the speed of the two bodies is the same, the equation would become

m_1u_1 = (m_1+m_2)v_f

Rearranging to find the velocity,

v_f = \frac{m_1u_1}{ (m_1+m_2)}

Replacing we have that,

v_f = \frac{(332)(2.3)}{ (332+19.5)}

v_f = 2.17 m/s

Therefore the velocity of the shark immediately after it swallows the tank is 2.17m/s

4 0
3 years ago
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