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Anna71 [15]
3 years ago
7

If a motorcycle covers 5km in 10 minutes , how far does it move in 1 second ?​

Physics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

A motorcycle moves 5km in 10 minutes(10×60s=600 seconds)

A motorcycle moves 5/600 km in 1 second.

A motorcycle moves 1/120 km in 1 second.( 5/600 = 1/120)

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What is the difference between tangential acceleration and centripetal acceleration?
Nuetrik [128]

Centripetal acceleration is directed along a radius so it may also be called the radial acceleration. If the speed is not constant, then there is also a tangential acceleration (at). The tangential acceleration is, indeed, tangent to the path of the particle's motion.

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3 years ago
What happens when you get a concussion?
madreJ [45]
A concussion, which is a form of mild traumatic brain injury, occurs after a blow to the head. The brain is surrounded by fluid and protective membranes called meninges, which usually cushion the brain. During an impact, the brain is pushed against the inside of the skull and can be bruised.
6 0
3 years ago
Why can concave mirror is used in cosmetic mirror​
tatuchka [14]

Answer:

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3 years ago
A vector is expressed in polar notation as A⃗ = ( 35.0 N, 37 ∘) Calculate the components of the vector, and enter them (separat
Aleks04 [339]

Answer:

A = (27.95 N, 21 N)

Explanation:

The polar co-ordinates are given as:

(r,θ) = (35 N, 37°)

Now, to convert this into polar co-ordinates (x, y), we will use following relations:

r² = x² + y²

(35)² = x² + y²

1225 = x² + y²  ----------- equation (1)

and

tan θ = y/x

tan 37° = y/x

y =  0.753 x   ------------------- equation (2)

Substituting this value in equation (1):

1225 = x² + (0.753 x)²

1225 = 1.567 x²

x² = 1225/1.567

x = √781.32

x = 27.95 N

using this value in equation (2)

y = (0.753)(27.95 N)

y = 21 N

Therefore, the vector can be represented in polar co-ordinates as:

<u>A = (27.95 N, 21 N)</u>

7 0
3 years ago
Aunt Mary needs to hang a picture in her bedroom. She uses a hammer to drive the nail into the wall. Find the force exerted by t
Cerrena [4.2K]

t = time of contact of hammer with the nail = 0.4 sec

I = impulse exerted by the hammer on the nail = 32 N s

F = force applied by the hammer on the nail

we know that , impulse is given as

I = F t                  where I = impulse , F = force , t = time

hence the impulse of hammer on nail is given as

I = F t

inserting the values

32 Ns = F (0.4 sec)

F = 32/0.4

F = 80 N

hence the force exerted by the hammer comes out to be 80 N


4 0
3 years ago
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