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levacccp [35]
3 years ago
6

B. A 20kg wagon is pulled up a 30° incline at an acceleration of 2.5ms?. The force pulling the wagon is parallel to the incline

and its value is 182N. Determine the value of the co-efficient of kinetic friction. [5]​
Physics
1 answer:
yawa3891 [41]3 years ago
7 0

The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

<h3>Coefficient of the kinetic friction</h3>

The value of coefficient of kinetic friction is calculated as follows;

F - Ff = ma

F - μmgcosθ = ma

where;

  • F is applied force
  • μ is coefficient of kinetic friction
  • m is mass of the wagon
  • a is acceleration of the wagon

182 - μ(20 x 9.8 x cos30) = 20(2.5)

182 - 169.74μ = 50

182 - 50 = 169.74μ

132 = 169.74μ

μ = 132/169.74

μ = 0.78

Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

Learn more about coefficient of friction here: brainly.com/question/20241845

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6 0
3 years ago
A truck covers 40.0 m in 7.10 s while smoothly slowing down to a final velocity of 2.75 m/s.. (a) Find the truck's original spee
ser-zykov [4K]
D = vo t - at²/2
v = vo - at
40 m = vo · 7.10 - a · ( 7.10 )²/2
40 m = 7.10 vo - a· 50.41/2
40 m = 7.10 vo - 25.205 a
2.75 m/s = vo - 7.10 a   ⇒  a = ( vo - 2.75 )/ 7.10
40 = 7.10 vo - 25.205 · ( vo - 2.75 ) / 7.10
40 = 7.1 vo - 3.55 vo + 9.7625
3.55 vo = 30.2375 
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Answer: the truck`s original speed is 8.5176 m/s.
 
4 0
4 years ago
S A block of mass M is connected to a spring of mass m and oscillates in simple harmonic motion on a frictionless, horizontal tr
cestrela7 [59]

The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².

<h3>What is kinetic energy?</h3>

Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).

<h3>How to calculate kinetic energy?</h3>

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

  • K.E represents the kinetic energy.
  • m represents the mass.
  • v represents the speed or velocity.

Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:

dK = 1/2 × (dm)Vx²

This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:

K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx

K.E = 1/2 × (M + m/3)v².

Read more on kinetic energy here: brainly.com/question/15848455

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6 0
2 years ago
A car slows down from 27.7 m/s to 10.9 m/s in 2.37 s, what is the acceleration?
larisa [96]

Answer:

Answer. to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs. So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2

Explanation:

4 0
3 years ago
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