Al will have a higher first and third ionization energy
It is B, and also for a moment I didn't understand that 4.69 x 10^22. I almost did this whole problem wrong.
The answer is 3/4.
The coefficient next to each reactant represents the amount of moles. The compound for oxygen is O2 and the compound for aluminum is 4. We can see that the number next to O2 is 3 and the number next to aluminum is 4.
Use a ratio to find out that x/190.2 = 74.5/100
hope this helps
