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tatiyna
3 years ago
15

The force generated by a single muscle fiber can be increased by increasing is called

Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

The force generated by a single muscle fiber can be increased by increasing the frequency of action potentials

Explanation:

The force generated by a muscle fiber is the result of the shortening of the skeletal muscle, and this force is also know as muscle tension. The larger motor units shorten along with the smaller units to produce the muscle force. The time lapsed between the beginning of the action potential in the muscle and the beginning of the contraction is the latent period. Action potential is the result of the difference electrical potential as a result of passage of an impulse along the membrane of a muscle or nerve cell.

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A force of 200N due South and another force of 300N due East each act on an object simultaneously.
dangina [55]

Answer:

a) 500

b)-500, north west

Explanation:

a) sum of F= F1+F2= 200+300= 500

b) sum of forces=0

so 200+300-500+0

4 0
2 years ago
A shopping cart is given an initial velocity of 4 m/s and experiences a constant acceleration of 4 m/s2. What is the magnitude o
NNADVOKAT [17]

Answer:

48m

Explanation:

  • Initial velocity = 4m/s
  • Acceleration = 4m/s²
  • Time = 4s
  • Displacement = ?

From Second equation of motion ,

\longrightarrow s = ut + 1/2at²

\longrightarrow s = 4*4 + 1/2*4*(4)² m

\longrightarrow s = (16 + 2 * 16) m

\longrightarrow s = ( 16 + 32 )m

\longrightarrow s = 48 m

8 0
3 years ago
Help hurry help pls it’s timed
Jobisdone [24]

Answer:

its the teal/second from the left one

Explanation:

4 0
2 years ago
Read 2 more answers
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentrati
Elina [12.6K]

Explanation:

1) N₂ + O₂ → 2 NO

Kc = [NO]² / ([N₂] [O₂])

Set up an ICE table:

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right]

Plug into the equilibrium equation and solve for x.

1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))

1.00×10⁻⁵ = (2x)² / (0.114 − x)²

√(1.00×10⁻⁵) = 2x / (0.114 − x)

0.00316 = 2x / (0.114 − x)

0.00361 − 0.00316x = 2x

0.00361 = 2.00316x

x = 0.00018

The volume is 1.00 L, so the concentrations at equilibrium are:

[N₂] = 0.114 − x = 0.11382

[O₂] = 0.114 − x = 0.11382

[NO] = 2x = 0.00036

2(a) Cl₂ → 2 Cl

Kc = [Cl]² / [Cl₂]

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right]

1.2×10⁻⁷ = (2x)² / (2 − x)

1.2×10⁻⁷ (2 − x) = 4x²

2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²

2.4×10⁻⁷ ≈ 4x²

x² ≈ 6×10⁻⁸

x ≈ 0.000245

2x ≈ 0.00049

2(b) F₂ → 2 F

Kc = [F]² / [F₂]

\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right]

1.2×10⁻⁴ = (2x)² / (2 − x)

1.2×10⁻⁴ (2 − x) = 4x²

2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²

2.4×10⁻⁴ ≈ 4x²

x² ≈ 6×10⁻⁵

x ≈ 0.00775

2x ≈ 0.0155

F₂ dissociates more, so Cl₂ is more stable at 1000 K.

7 0
3 years ago
What happens to reactants when a chemical reaction takes place?
yanalaym [24]

Answer:

they collide with one another

5 0
3 years ago
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