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SSSSS [86.1K]
3 years ago
5

Which nucleus completes the following equation?

Physics
2 answers:
IgorLugansk [536]3 years ago
4 0

Answer: ^{50}_{25}Mn\rightarrow ^{0}_1e+ ^{50}_{24}Cr

The chromium nucleus will complete the reaction.

Explanation:

The given reaction is a type of radioactive nuclei decay:

Positron emission: It is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. This is also known as \beta ^+-decay. In this the mass number remains same.

_A^Z\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

Now according to the given reaction:

^{50}_{25}Mn\rightarrow ^{0}_1e+ ^{50}_{24}Cr

The chromium nucleus will complete the reaction.

Olegator [25]3 years ago
4 0

Answer:

50 25 Mn-0 1 e+ 50 24 Cr

Explanation:

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552000 in scientific notation
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5.52 × 10 to the 5th power (100000)  . In scientific notation you need to have a decimal numver times 10 to the power of something so you can divide 552000 by 10  5  times. So in order to get 552000 you need to have 10 to the 4th power and 5.52
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3 years ago
A very long uniform line of charge has charge per unit length λ1 = 4.68 μC/m and lies along the x-axis. A second long uniform li
Kitty [74]

Answer:

E_{net} = 6.44 \times 10^5 N/C

Explanation:

As we know that electric field due to infinite line charge distribution at some distance from it is given as

E = \frac{2k \lambda}{r}

now we need to find the electric field at mid point of two wires

So here we need to add the field due to two wires as they are oppositely charged

Now we will have

E_{net} = \frac{2k\lambda_1}{r} + \frac{2k\lambda_2}{r}

now plug in all data

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\lambda_2 = 2.48 \mu C/m

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now we have

E_{net} = \frac{2k}{r}(4.68 + 2.48)

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8 0
3 years ago
A boy throws a ball of mass 0.22 kg straight upward with an initial speed of 29 m/s. When the ball returns to the boy, its speed
maksim [4K]

Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is \frac{1}{2} *m*(vf^{2} -vi^{2} )

You know:

  • mass=m=0.22 kg
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Final velocity of the ball: vf= 15 \frac{m}{s}

Replacing:

\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )= -67.76 J

Friction work is always negative because friction is always against displacement.

<u><em>The work is -67.76 J</em></u>

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