All categories

3 years ago

PLEASE HELP WILL GIVE 25 POINTS!!!!!

Physics

2 answers:

zimovet [89]3 years ago

8 0

The answer is B. 1,4, and 6

icang [17]3 years ago

5 0

Answer : The correct option is, (B) 1, 4, and 6

Explanation :

Boyle's Law : It is defined as the pressure is inversely proportional to the volume of the gas at constant temperature and number of moles. In this volume of gas changes.

$P\propto \frac{1}{V}$

Charles' Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles. In this volume of gas changes.

$V\propto T$

Gay-Lussac's Law : It is defined as the pressure is directly proportional to the temperature of the gas at constant volume and number of moles. In this volume of gas is constant.

$P\propto T$

Therefore, the volume should be placed in cell numbered 1, 4, and 6.

You might be interested in

An astronaut finds herself in a predicament in which she has become untethered from her shuttle. She figures that she could get

Blizzard [7]

In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.

The equation that defines the linear moment is given by

$mV_i = (m-m_O)V_f - m_OV_O$

where,

m=Total mass

$m_O =$ Mass of Object

$V_i =$ Velocity before throwing

$V_f =$ Final Velocity

$V_O =$ Velocity of Object

Our values are:

$m_1=5.3kgm_2=7.9kg\\m_3=10.5kg\\m_A=75kg\\m_{Total}=m=98.7Kg$

Solving to find the final speed, after throwing the object we have

$V_f=\frac{mV_0+m_TV_O}{m-m_O}$

We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.

That way during each section the equations should be modified depending on the previous one, let's start:

A) $5.3Kg\rightarrow 15m/s$

$V_{f1}=\frac{mV_0+m_TV_O}{m-m_O}$

$V_{f1}=\frac{(98.7)*0+5.3*15}{98.7-5.3}$

$V_{f1}=0.8511m/s$

B) $7.9Kg\rightarrow 11.2m/s$

$V_{f2}=\frac{mV_{f1}+m_TV_O}{m-m_O}$

$V_{f2}=\frac{(98.7)(0.8511)+(7.9)(11.2)}{98.7-5.3-7.9}$

$V_{f2} = 2.0173m/s$

C) $10.5Kg\rightarrow 7m/s$

$V_{f3}=\frac{mV_{f2}+m_TV_O}{m-m_O}$

$V_{f3}=\frac{(98.7)(2.0173)+(10.5)(7)}{98.7-5.3-7.9-10.5}$

$V_{f3} = 3.63478m/s$

Therefore the final velocity of astronaut is 3.63m/s

7 0

3 years ago

Properties seen when one substance changes to another are know as ____ properties

maxonik [38]

Answer: chemical property

Explanation:

6 0

2 years ago

Read 2 more answers

A car drives 23m/s east for 35 seconds. What is the displacement?

Lina20 [59]

Answer:

805m

Explanation:

Speed = displacement/time

Speed = 23m/s

Time = 35s

Displacement = speed × time

= 23 × 35

= 805m

5 0

3 years ago

Some earthquake waves, a cat’s purr, and elephant communications consist of ultrasonic waves.

Kobotan [32]

The answer to your question is true.

7 0

3 years ago

Read 2 more answers

At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.390 m is the magnitude of

aliina [53]

<span>Radius, the distance from the centre = 0.390
Electric field is equal to half of the magnitude. E2 = E / 2
Given
E1 = E2 E1 = k x Q / r^2
E2 = (k x Q / r2^2) / 2
Equating the both we get 2 x r^2 = r2^2
r2 = square root of (2 x r1^2) = square root of (2) x r = 1.414 x 0.390
r2 = 1.414 x 0.390 = 0.551 m</span>

3 0

3 years ago