All categories

3 years ago

PLEASE HELP WILL GIVE 25 POINTS!!!!!

Physics

2 answers:

zimovet [89]3 years ago

8 0

The answer is B. 1,4, and 6

icang [17]3 years ago

5 0

Answer : The correct option is, (B) 1, 4, and 6

Explanation :

Boyle's Law : It is defined as the pressure is inversely proportional to the volume of the gas at constant temperature and number of moles. In this volume of gas changes.

$P\propto \frac{1}{V}$

Charles' Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles. In this volume of gas changes.

$V\propto T$

Gay-Lussac's Law : It is defined as the pressure is directly proportional to the temperature of the gas at constant volume and number of moles. In this volume of gas is constant.

$P\propto T$

Therefore, the volume should be placed in cell numbered 1, 4, and 6.

You might be interested in

A tiger travels 3m/s^2 for 4.1s,what was its initial speed if it's final speed was 55k/h?

zaharov [31]

Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)

8 0

3 years ago

Which of the three recording stations was closest to the epicenter of the earthquake, based on the seismograms shown below?

Nastasia [14]

Answer:C

Explanation:took quiz

3 0

3 years ago

Read 2 more answers

A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential differen

leva [86]

The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

Work function is a material property defined as the minimum amount of energy required to infinitely remove electrons from the surface of a particular solid.
The potential difference required to support all emitted electrons is called the stopping potential which is given by $v_0=\frac{K.E_m_a_x}{e}$ .....(1)
where $v_0$ is the stopping potential and e is the charge of the electron given by $1.6\times10^-^1^9$ .

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation is given by:

$K.E_m_a_x=E-\phi$ ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

$ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV$

As we know that $E=\frac{hc}{\lambda}$ ....(3)

where Speed of light, $c = 3\times10^8 m/s$ and Planck's constant , $h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs$

From equation (3) , we get

$\lambda=\frac{hc}{E} \\\\\lambda=\frac{ 4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm$