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2 years ago

30 points must be a legitimate answer and correct answer or I will report

Physics

2 answers:

serious [3.7K]2 years ago

8 0

The correct answer is C !

kupik [55]2 years ago

6 0

Answer:

it's C

Explanation:

have a nice day............

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X-Rays at different wavelengths provide scientists studying objects in space with information about which of the following?

olganol [36]

Answer:

object composition

Explanation:

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3 years ago

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The speed of the center of the earth as it orbits the sun is 107257 kmph and the absolute angular velocity of the earth about it

Sindrei [870]

Answer with Explanation:

We are given that

Speed , $v_0$ =107257 kmph

Angular velocity, $\omega=7.292\times 10^{-5} rad/s$

Radius of earth,r= $6371 km=6371000 m$

1 km=1000 m

Linear velocity, $v=r\omega=6371000\times 7.292\times 10^{-5}=464.57 m/s$

Linear velocity, $v=464.57\times \frac{18}{5}=1672.46 km/h$

Velocity at point A, $v_A=-vi+v_0 j=-1672.46 i+107257j kmph$

Velocity at point B, $v_B=v_0j-vj=107257j-1672.46j=105584.54j kmph$

Velocity at point C, $v_C=v_0j+vi=1672.46 i+107257j kmph$

Velocity at point D, $v_D=v_0j+vj=107257j+1672.46j=108929.46jkmph$

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3 years ago

What are the fundamental units involved in pascal<br>

Llana [10]

Answer:

<h2>FUNDAMENTAL UNITS INVOLVED ARE : NEWTON AND SECOND .</h2>

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3 years ago

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Without heat from the Sun, the water cycle would A) reverse. B) not work. C) slow down. D) not be affected.

Tanzania [10]

B) not work ,because the water would freeze

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3 years ago

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Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho

8090 [49]

Answer:

Hoop will reach the maximum height

Explanation:

let the mass and radius of solid ball, solid disk and hoop be m and r (all have same radius and mass)

They all are rolled with similar initial speed v

by the law of conservation of energy we can write

$K_{trans}+K_{rot}= P$

for solid ball

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}$

putting $I_{ball}=\frac{2}{5}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{ball}= 0.071v^2$

now for solid disk

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}$

putting $I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{disk}= 0.076v^2$

for hoop

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}$

putting $I_{hoop}=mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{hook}= 0.10v^2$

clearly from the above calculation we can say that the Hoop will reach the maximum height

5 0

3 years ago