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WARRIOR [948]
3 years ago
5

imine formation is an acid-catalyzed process, however the procedure performed in this does not require the addition of an extern

al acid. Suggest a viable source of acid in the reaction depicted.

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

See explaination

Explanation:

Reaction between p- toluidine and o- vaniline to form imine.This reaction does occur in the presence of a acidic source.

Here the -OH group in the o- vaniline is quite acidic so it acts a internal acidic catalyst. Hence the reaction occurred in the absence of any external acidic source.The reaction mechanism is given at the attached file.

please kindly see attachment.

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Explanation:

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(Chemistry) Match each item with the correct statement below.
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3 years ago
The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con
bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is 3.83\times 10^{-30}mol/L

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=3.82days

Putting values in above equation, we get:

k=\frac{0.693}{3.82}=0.181days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 0.181days^{-1}

t = time taken for decay process = 3.00 days

[A_o] = initial amount of the reactant = 1.45\times 10^{-6}mol/L

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}

[A]=3.83\times 10^{-30}mol/L

Hence, the concentration of radon after the given time is 3.83\times 10^{-30}mol/L

7 0
4 years ago
A soccer player applies a force of 56.6 N to a soccer ball while kicking it. If the ball has a mass of 0.46 kg, what is the acce
lubasha [3.4K]

Answer:

a=123.04\ m/s^2

Explanation:

Given that,

Force applied to a soccer player, F = 56.6 N

The mass of the ball, m = 0.46 kg

We need to find the acceleration of the soccer ball. The force acting on the ball is given by :

F = ma

Where

a is the acceleration

a=\dfrac{F}{m}\\\\a=\dfrac{56.6 }{0.46 }\\\\a=123.04\ m/s^2

So, the required solution is 123.04\ m/s^2.

3 0
3 years ago
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