imine formation is an acid-catalyzed process, however the procedure performed in this does not require the addition of an extern
al acid. Suggest a viable source of acid in the reaction depicted.
1 answer:
Answer:
See explaination
Explanation:
Reaction between p- toluidine and o- vaniline to form imine.This reaction does occur in the presence of a acidic source.
Here the -OH group in the o- vaniline is quite acidic so it acts a internal acidic catalyst. Hence the reaction occurred in the absence of any external acidic source.The reaction mechanism is given at the attached file.
please kindly see attachment.
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A. The abundance of the 2nd isotope is 48.119%
B. The mass of the 2nd isotope is 108.905 amu
Let the 1st isotope be A
Let the 2nd isotope be B
A. Determination of the abundance of the 2nd isotope
Abundance of isotope A = 51.881%.
<h3>Abundance of isotope B =? </h3>Abundance of B = 100 – A
Abundance of B = 100 – 51.881
<h3>Abundance of B = 48.119%</h3>B. Determination of the mass of the 2nd isotope
Atomic mass of silver = 107.868 amu.
Mass of 1st isotope (A) = 106.906 amu
Abundance of isotope A (A%) = 51.881%.
Abundance of isotope B (B%) = 48.119%
<h3>Mass of 2nd isotope (B) =? </h3>Therefore, the mass of the 2nd isotope is 108.905 amu
Learn more: brainly.com/question/7955048
The energy released when electron move from n=4 to n=3 is 0.66 eV
We know that in an atom energy of nth state is
eV
where n is the energy level
Therefore,
Thus, = -0.85eV
= -1.51eV
Therefore, total mount of energy released in moving electron from n=4 to n=3 is given by -
= -0.85 - ( -1.51)
= 0.66eV
To know more about energy released in electron transition
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