The period of the pendulum is given by the following equation
T = 2<span>π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g
g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2
The answer is A. 446.9 J
Solution:
W = mgh
W = (3.8 Kg)(9.8 m/s²)(12 m)
W = 446.88 J or 446.9 J
Examples of Newton's Second Law of Motion
Pushing a Car and a Truck. ...
Pushing a Shopping Cart. ...
Two People Walking Together. ...
Hitting a Ball. ...
Rocket Launch. ...
Car Crash. ...
Object thrown from a Height. ...
Karate Player Breaking Slab of Bricks.