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3 years ago

Please help I'll give brainliest!!

Physics

2 answers:

photoshop1234 [79]3 years ago

4 0

Answer:

this may be wrong but when i looked it up it said “Seafloor Mapper”

Explanation:

Llana [10]3 years ago

3 0

Answer:

the technology and research for your career is the tech used is sonar tracker or map as well as the technology and research used is to track the habitants of the ocean floor

Explanation:

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The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c

maria [59]

To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

$E= \frac{kQ}{R^2}$

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

$Q = \frac{ER^2}{k}$

Replacing,

$Q = frac{(150)(6.38*10^6)}{8.99*10^9}$

$Q = 6.79*10^5 C$

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

$F_w = F_e$

$mg = \frac{kQq}{R^2}$

Replacing,

$(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}$

Solving for q,

$q = -4.056C$

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

$F =\frac{kq^2}{d^2}$

$F = \frac{(8.99*10^9)(-4.056)^2}{110^2}$

$F = 1.22*10^7N$

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

3 0

2 years ago

A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e

Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

$F=20\times 10^9 Hz$

$\Delta F=F_r-F_t=4750 Hz$

c = Speed of light = 3×10⁸ m/s

Relative speed

$v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s$

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0

3 years ago

A boy of 50 kg jumps off a boat (30 kg), causing the boat to move to the right at 2.0 m/s. In what direction and at what velocit

LUCKY_DIMON [66]

By Newtons Third law this is an action reaction pair of force
So the momentum is the same
30*20=50*x where x is velocity
x= 12m/s
direction is towards left since they act in opposite directions

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2 years ago

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How do mass and force affect the acceleration of an object?

joja [24]

Gravity affects weight, it does not affect mass. Masses always remain the same. Newton's Second Law of Motion: Force = mass x acceleration The acceleration of an object is: a) directly proportional to the net force acting on the object. ... c) inversely proportional to the mass of the object.

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3 years ago

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What type of wave travels through matter only??

Olenka [21]

A mechanical wave can only travel through matter.

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2 years ago

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