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2 years ago

Hello people ~

Physics

1 answer:

Fantom [35]2 years ago

3 0

Explanation:

In di electric medium

The force is

$\sf F_{dE}=\dfrac{1}{4K\pi\epsilon}\dfrac{q_1q_2}{R^2}$

So the force on air is decreased k times

Option C is correct

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Your current exam mean is 97.2. if you receive a 99 on the next exam, this will have the effect of ______.

GarryVolchara [31]

If your current exam mean is 97.2. and you receive a 99 on the next exam, then this will have the effect of increasing the mean.

In statistics, the mean is an average value used to calculate when taking different measurements, which can be fundamental to collecting statistically significant information.

In conclusion, if your current exam mean is 97.2. and you receive a 99 on the next exam, then this will have the effect of increasing the mean.

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8 0

1 year ago

For a certain RLC circuit the maximum generator EMF is 125 V and the maximum current is 3.20 A. If le a) the impedance of the ci

MAXImum [283]

Answer:

Part (i)

Z = 39.06 ohm

Part (ii)

R = 21.7 ohm

Explanation:

a) here we know that

maximum value of EMF = 125 V

maximum value of current = 3.20 A

now by ohm's law we can find the impedence as

$z = \frac{V_o}{i_o}$

now we will have

$z = \frac{125}{3.20} = 39.06 ohm$

Part b)

Now we also know that

$\frac{R}{z} = cos\theta$

$\theta = 0.982 rad = 56.3 degree$

now we have

$\frac{R}{39.06} = cos56.3$

$R = 21.7 ohm$

5 0

3 years ago

Two coconuts fall freely from rest at the same time, one from a tree twice as high as the other. If the coconut from the shorter

valentinak56 [21]

Wee can use here kinematics

as we know that

$y = v*t + \frac{1}{2} at^2$

for shorter tree we know that

$y = 0 + \frac{1}{2}*9.8 * 2^2$

$y = 19.6 meter$

now since we know that other tree is twice high

So height of other tree is y = 39.2 m

now again by above equation

$y = v*t + \frac{1}{2} at^2$

$39.2 = 0 + \frac{1}{2}*9.8 * t^2$

$t = 2.83 s$

so the time taken is 2.83 s

4 0

2 years ago

Neutron stars consist only of neutrons and have unbelievably high densities. a typical mass and radius for a neutron star might

Tanya [424]

<span>Density is 3.4x10^18 kg/m^3 Dime weighs 1.5x10^12 pounds The definition of density is simply mass per volume. So let's divide the mass of the neutron star by its volume. First, we need to determine the volume. Assuming the neutron star is a sphere, the volume will be 4/3 pi r^3, so 4/3 pi 1.9x10^3 = 4/3 pi 6.859x10^3 m^3 = 2.873x10^10 m^3 Now divide the mass by the volume 9.9x10^28 kg / 2.873x10^10 m^3 = 3.44588x10^18 kg/m^3 Since we only have 2 significant digits in our data, round to 2 significant digits, giving 3.4x10^18 kg/m^3 Now to figure out how much the dime weighs, just multiply by the volume of the dime. 3.4x10^18 kg/m^3 * 2.0x10^-7 m^3 = 6.8x10^11 kg And to convert from kg to lbs, multiply by 2.20462, so 6.8x10^11 kg * 2.20462 lb/kg = 1.5x10^12 lb</span>

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3 years ago

A car with two people traveling down the road has a mass of 100 kg and a velocity of 5 m/s. The car pulls over and picks up two

Andrej [43]

Answer:

New_momentum = 750 [kg.m/s]

Explanation:

Momentum is defined as

M = mass* velocity

Original momentum

M_old = 100 Kg * 5 m/s = 500 [kg.m/s]

If the car pulls over and picks up two people. The mass of the car is now 150 kg, but the velocity stays the same.

New momentum

M_new = 150 Kg * 5 m/s = 750 [kg.m/s]

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2 years ago