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1 year ago

What would most likely happen if the decomposers were removed from the food web?

Physics

1 answer:

Rufina [12.5K]1 year ago

8 0

D. The decaying matter would not be returned back into the environment.

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Two forces whose resultant is 100newton are perpendicular to each other. If one of them makes an angle of 60newton with the resu

Elis [28]

Answer:

100 N

Explanation:

Given that,

Two forces whose resultant is 100newton are perpendicular to each other.

If one of them makes an angle of 60newton with the resultant.

$F_1=100\times \sin60=86.60\ N$

and

$F_2=100\times \cos60=50\ N$

The magnitude of force,

$F=\sqrt{F_1^2+F_2^2} \\\\F=\sqrt{86.6^2+50^2} \\\\F=99.99\ N$

F = 100 N

So, the magnitude of force is 100 N.

6 0

2 years ago

Calculate

Fed [463]

The speed of the spacecraft in this orbit

8 0

3 years ago

after a circuit has been turned off, so it is important to make sure they are discharged before you touch them. Suppose a 120 mF

Snezhnost [94]

Answer:

The time is $110.16\times10^{-3}\ sec$

Explanation:

Given that,

Capacitor = 120 μF

Voltage = 150 V

Resistance = 1.8 kΩ

Current = 50 mA

We need to calculate the discharge current

Using formula of discharge current

$i_{0}=\dfrac{V_{0}}{R}$

Put the value into the formula

$i_{0}=\dfrac{150}{1.8\times10^{3}}$

$i_{0}=83.3\times10^{-3}\ A$

We need to calculate the time

Using formula of current

$i=\dfrac{V_{0}}{R}e^{\frac{-t}{RC}}$

Put the value into the formula

$50=\dfrac{150}{1.8\times10^{3}}e^{\frac{-t}{RC}}$

$\dfrac{50}{83.3}=e^{\frac{-t}{RC}}$

$\dfrac{-t}{RC}=ln(0.600)$

$t=0.51\times1.8\times10^{3}\times120\times10^{-6}$

$t=110.16\times10^{-3}\ sec$

Hence, The time is $110.16\times10^{-3}\ sec$

4 0

3 years ago

What did the scientists deduce from the fact that the ants eyes of the desert have multiple lenses

Evgesh-ka [11]

That the pupl is smaller than the nulian hope this helped

4 0

3 years ago

In a football game, a 90 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi

irinina [24]

To solve this problem it is necessary to apply the equations related to the conservation of momentum. Mathematically this can be expressed as

$m_1v_1+m_2v_2 = (m_1+m_2)v_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial velocity of each object

$v_f$ = Final Velocity

Since the receiver's body is static for the initial velocity we have that the equation would become

$m_2v_2 = (m_1+m_2)v_f$

$(0.42)(21) = (90+0.42)v_f$

$v_f = 0.0975m/s$

Therefore the velocity right after catching the ball is 0.0975m/s

8 0

3 years ago