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Ksju [112]
3 years ago
7

Gifblaar is a small South African shrub and one of the most poisonous plants known because it contains fluoroacetic acid (FCH2CO

OH), which has a pKa of 2.59. Calculate the concentration of fluoroacetic acid in a solution that has the same pH as a 0.00770 M solution of HCl
Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
4 0

[H_{3}O^{+}] = 0.00770 M

The equilibrium equation representing the dissociation of FCH_{2}COOH

FCH_{2}COOH(aq) + H_{2}O (l)    FCH_{2}COO^{-}(aq)+ H_{3}O^{+}(aq)

Given [H_{3}O^{+}] = 0.00770 M

Let the initial concentration of acid be x and change y

So y = [H_{3}O^{+}] =[FCH_{2}COO^{-}] = 0.00770 M

pK_{a} = 2.59K_{a} = 10^{-2.59}   = 0.00257 M

K_{a} = \frac{(0.00770 M)(0.00770 M)}{x - 0.00770}

0.00257 = \frac{0.00005929}{x - 0.00770}

0.00257 x - 0.00001979 = 0.00005929

x = 0.031 M

Therefore, initial concentration of the weak acid is <u>0.031 M</u>

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An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci
lapo4ka [179]

Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = \frac {Excess}{Total\ Concentration}\times 100 = \frac {11.5-1.5}{11.5+1.5}\times 100 = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = \frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100

Optical rotation of pure enantiomer = −127 °

76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100

<u>Specific rotation of mixture = - 97.6923 °</u>

6 0
3 years ago
How do you figure out molality
hodyreva [135]
*The molality of a solution is calculated by taking the moles of solute and dividing by
the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until all the solid was gone. We
then made sure everything was well-mixed.
What would be the molality of this solution? Notice that my one liter of water weighs
1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).
3 0
2 years ago
the atomic masses of 63 cu (69.17 percent) and 65 cu (30.83 percent) are 62.94 and 64.93 amu, respectively. calculate the averag
docker41 [41]

Answer:

The average atomic mass of copper is 63.55 amu.

Explanation:

hope this help

7 0
2 years ago
777 Joules of energy are applied to 25.0 grams of each of the following materials, which
4vir4ik [10]

Answer:

I think copper

Explanation:

Material IACS % Conductivity

Silver                105

Copper            100

Gold               70

Aluminum         61

Nickel              22

Zinc                          27

Brass                  28

Iron                        17

Tin                      15

Phosphor Bronze  15

Lead                      7

Nickel Aluminum Bronze 7

Steel                   3 to 15

the table might help- your indian brother

3 0
3 years ago
Convert 675 nanograms to milligrams.
STALIN [3.7K]

675 nanograms is equivalent to 6.75 × 10-⁴ milligrams.

<h3>How to convert nanograms to milligrams?</h3>

Nanograms is a unit of mass equal to 0.000000001 grams and has a symbol of ng.

On the other hand, milligrams is another unit of mass equal to 0.001grams and has a symbol of mg.

Nanograms and milligrams are both units of mass and can be inter-convertible as follows:

1 nanogram = 1 × 10-⁶ milligram

According to this question, 675 nanograms is equivalent to 675 × 10-⁶ milligrams.

Therefore, 675 nanograms is equivalent to 6.75 × 10-⁴ milligrams.

Learn more about milligrams at: brainly.com/question/20320382

#SPJ1

7 0
2 years ago
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