Answer:
Mass = 1080.26 g
Explanation:
Given data:
Number of moles of LaPO₄ = 4.56mol
Mass in gram = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of LaPO₄ = 236.9 g/mol
by putting values,
4.56 mol = mass/ 236.9 g/mol
Mass = 4.56 mol × 236.9 g/mol
Mass = 1080.26 g
Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.
<h3>What is concentration?</h3>
The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.
Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.
Thus;
Ca(CH3COO)2(aq) ----> Ca^2+(aq) + 2CH3COO^-(aq)
It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.
Learn more about concentration:brainly.com/question/10725862
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Answer:
Since both H2 and H2O have the same ratio in the balanced equation, if you have 20 moles of H2 you will also get 20 moles of H20.
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Answer:
Explanation:
It is given that,
Number of moles, n = 0.15
We need to find the number of particles in 0.15 mol of NaCl. Let N are the number of particles i.e.
Number of particles = number of moles × Avagadro's number
So,
So, the number of particles are .