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skad [1K]
3 years ago
5

The ph scale for acidity is defined by ph=−log10[h+] where [h+]is the concentration of hydrogen ions measured in moles per liter

(m).a solution has a ph of 2.55.
Chemistry
1 answer:
Leokris [45]3 years ago
7 0

The question is incomplete.

The complete question probably is

The pH scale for acidity is defined by pH = − log₁₀[H⁺] where [H⁺] is the concentration of hydrogen ions measured in moles per liter (M). A solution has a pH of 2.55. Find the hydrogen ion concentration.

Answer: -

0.003 M

Explanation: -

pH = − log₁₀[H⁺]

Thus the hydrogen ion concentration [H⁺] = 10^{-pH}

= 10^{-2.55}

= 0.003 M

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Which one does not share the same properties as the other
myrzilka [38]

Answer:

Ti

Explanation:

Ti is titanium and does not share any similar properties with the likes of Si, silicon and At, astatine.

  • Titanium is a transition metal and a solid.
  • Silicon and Astatine are non - metals.
  • Silicon and Astatine also belongs to the p-block on the periodic table whereas Titanium is found on the d-block.
  • Silicon and Astatine would prefer to take part in reactions where they can gain electrons because they are non metals whereas Titanium due to its metallic property would prefer a reaction where it can lose electrons.

5 0
2 years ago
How many kg of carbon dioxide are used per year to produce their arm and hammer baking soda?
cestrela7 [59]
The complete question would be as follows:

700,000 tons of baking soda are produced per year. <span>How many kilograms of carbon dioxide are used per year to produce baking soda?

We calculate as follows:

</span><span>CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)
</span>
700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (<span>1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2

Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
A 51.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by a
S_A_V [24]

Answer:

The final concentration is 0.226 M.

Explanation:

In this problem the dilution has occurred two times. So the symbol initial concentration, concentration after first dilution and the concentration after second dilution is given as C1, C2, and C3 respectively. Same can be done for the volume i.e, V1, V2, and V3 will be the initial volume, the volume taken after first dilution, and the volume after second dilution.

So, let's use the dilution formula for the first dilution

C_1 \times V_1 = C_2 \times V_2

C_2 = \frac{C_1\times V_1}{V_2}\\\\C_2 = \frac{1.50\times 51.0}{208}\\\\C_2 = 0.368 M

Now, for the second dilution

C_2 \times V_2 = C_3 \times V_3\\\\C_3 = \frac {C_2 \times V_2}{V_3}\\\\C_3 = \frac {0.368 \times 104}{169}\\\\C_3 = 0.226 M

6 0
3 years ago
Write the formula for each of the following. (a) sodium carbonate (b) sodium bicarbonate (c) carbonic acid (d) hydrofluoric acid
user100 [1]

(A) Na2CO3

(B) NaHCO3

(C) H2CO3

(D) HF

(E) SO3

(F) CuSO4

(G) H2SO4

(H) H2S

- Remember to place the subscripts correctly. Hope I helped.

6 0
3 years ago
Read 2 more answers
Scientists can learn about the chemical composition of stars by analyzing the light they transmit. true or false
e-lub [12.9K]
It is true
Hope this help
8 0
3 years ago
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