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Tju [1.3M]
3 years ago
10

Acetic acid has a boiling point of 118.5 C and a boiling point constant of 3.08. What is the boiling point of a 3.20 m solution

of Ca(NO3)2 in acetic acid?
Chemistry
1 answer:
puteri [66]3 years ago
6 0

Answer:

T = 401.356 K (128.356°C)

Explanation:

boiling point:

  • ΔT = K×m = T - T*

∴T: boiling temperature of the solution

∴ T*: boiling temperature of pure solvent = 118.5°C ≅ 391.5 K

∴ K: boiling point constant = 3.08 K.Kg/mol

∴ m: molality [=] mol/Kg = 3.20 m

∴  solvent: acetic acid

∴  solute: Ca(NO3)2

⇒ T = T* + (K)(m)

⇒ T = 391.5 K + ((3.08 K.Kg/mol)(3.20 mol/Kg))

⇒ T = 391.5 K + 9.856 K

⇒ T = 401.356 K

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A vascular plant is any one of a number of plants with specialized vascular tissue. The two types of vascular tissue, xylem and phloem, are responsible for moving water, minerals, and the products of photosynthesis throughout the plant.

Explanation:

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3 years ago
3. 200 ml of 0.2 M HCl is neutralized with 0.1 M
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Answer:

  • <u><em>a. 0.1 M</em></u>

Explanation:

By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.

The neutralization reaction that you are studying is the acid-base reaction:

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Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:

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3 years ago
Name this compound Cr2(CO3)3
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Molecular Weight

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What are the four phases of matter?
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A sample of a mineral solid weighing 28.5 g was added to a graduated cylinder filled with to a level of 20.3 mL. As a result, th
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Answer:

2.8 g/mL is the density of the mineral.

Explanation:

The mass, m=28.5\ g

Volume of the object = Volume of water level rose - Initial volume of water = 30.5 mL - 20.3 mL = 10.2 mL

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

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<u>2.8 g/mL is the density of the mineral.</u>

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