Question

Acetic acid has a boiling point of 118.5 C and a boiling point constant of 3.08. What is the boiling point of a 3.20 m solution of Ca(NO3)2 in acetic acid?

Answer 1

Answer:

T = 401.356 K (128.356°C)

Explanation:

boiling point:

• ΔT = K×m = T - T*

∴T: boiling temperature of the solution

∴ T*: boiling temperature of pure solvent = 118.5°C ≅ 391.5 K

∴ K: boiling point constant = 3.08 K.Kg/mol

∴ m: molality [=] mol/Kg = 3.20 m

∴  solvent: acetic acid

∴  solute: Ca(NO3)2

⇒ T = T* + (K)(m)

⇒ T = 391.5 K + ((3.08 K.Kg/mol)(3.20 mol/Kg))

⇒ T = 391.5 K + 9.856 K

⇒ T = 401.356 K