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1 year ago

1. The s orbitals are not symmetrical in shape. a. TRUE O. FALSE

Chemistry

1 answer:

ira [324]1 year ago

4 0

The s orbitals are not symmetrical in shape is a FALSE statement.

An s orbital is so symmetric, more specifically spherically symmetric that it looks the same from all directions.

The atomic orbitals in the atoms of elements differ in shape.

In essence, the electrons they describe have varying probability distributions around the nucleus. The spherical symmetry of s orbitals is evident in the fact that all orbitals of a given shell in the hydrogen atom have the same energy.

All s orbitals are spherically symmetrical. Put simply, an electron that occupies an s orbital can be found with the same probability at any orientation (at a distance) from the nucleus.

The s orbitals are therefore represented by a spherical boundary surface which is a surface which captures a high proportion of the electron density.

Read more:

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3 years ago

Mass of metal=0.0291. Volume of gas collected over water=25.67mL. Temperature=24.1C. Atmospheric pressure=754.6mmHg. Note: Metal

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Answers:

1) 732.1 mmHg; 2) 0.001 014 mol; 3) 0.001 014 mol; 4) 28.7 g/mol; 5) 187 ppt.

Explanation:

1) Partial pressure of hydrogen

You are collecting the gas over water, so

$p_{\text{atm}} = p_{\text{H}_{2}} + p_{\text{H}_{2}\text{O}}$

$p_{\text{H}_{2}} = p_{\text{atm}} - p_{\text{H}_{2}\text{O}}$

$p_{\text{atm}} = \text{754.6 mmHg}$

At 24.1 °C, $p_{\text{H}_{2}\text{O}} = \text{22.5 mmHg}$

$p_{\text{H}_{2}} = \text{754.6 mmHg} - \text{22.5 mmHg} = \textbf{732.1 mmHg}$

===============

2) Moles of H₂

We can use the Ideal Gas Law.

pV = nRT Divide both sides by RT and switch

n = (pV)/(RT)

p = 732.1 mmHg Convert to atmospheres

p = 732.1/760 Do the division

p = 0.9633 atm

V = 25.67 mL Convert to litres

V = 0.025 67 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 24.1 °C Convert to kelvins

T = (24.1 + 273.15 ) K = 297.25 K Insert the values

n = (0.9633 × 0.025 67)/(0.082 06 × 297.25) Do the multiplications

n = 0.02473/24.39 Do the division

n = 0.001 014 mol

===============

3) Moles of metal

The partial chemical equation is

M + … ⟶ H₂ + …

The molar ratio of M:H₂ is 1 mol M:1 mol H₂.

Moles of M = 0.001 014 × 1/1 Do the operations

Moles of M = 0.001 014 mol M

===============

4) Atomic mass of M

Atomic mass = mass of M/moles of M Insert the values

Atomic mass = 0.0291/0.001 014 Do the division

Atomic mass = 28.7 g/mol

===============

5) Relative deviation in ppt

Your metal must be in Group 2 because of the 1:1 molar ratio of M:H₂.

The metal with the closest atomic mass is Mg (24.305 g/mol).

Relative deviation in ppt = |Experimental value – Theoretical value|/Theoretical value × 1000

Relative deviation = |28.7 – 23.405|/23.405 × 1000 Do the subtraction

Relative deviation = |4.39|/23.405 × 1000 Do the operations

Relative deviation = 187 ppt

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3 years ago