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2 years ago

1. The s orbitals are not symmetrical in shape. a. TRUE O. FALSE

Chemistry

1 answer:

ira [324]2 years ago

4 0

The s orbitals are not symmetrical in shape is a FALSE statement.

An s orbital is so symmetric, more specifically spherically symmetric that it looks the same from all directions.

The atomic orbitals in the atoms of elements differ in shape.

In essence, the electrons they describe have varying probability distributions around the nucleus. The spherical symmetry of s orbitals is evident in the fact that all orbitals of a given shell in the hydrogen atom have the same energy.

All s orbitals are spherically symmetrical. Put simply, an electron that occupies an s orbital can be found with the same probability at any orientation (at a distance) from the nucleus.

The s orbitals are therefore represented by a spherical boundary surface which is a surface which captures a high proportion of the electron density.

Read more:

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Answer:The Answer is D

Explanation:

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3 years ago

In your own words, describe what is the role or function of the neutron in the atom's nucleus

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3 years ago

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If 9.9L of helium are in a tire at 303k,how many liters will be present at 403k if the pressure is held constant.

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Answer:

Final volume, V2 = 13.18 Liters

Explanation:

Given the following data;

Initial volume = 9.9 L

Initial temperature = 303 K

Final temperature = 403 K

To find the final volume, we would use Charles law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

$VT = K$

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Where;

V1 and V2 represents the initial and final volumes respectively.
T1 and T2 represents the initial and final temperatures respectively.

$\frac{V1}{T1} = \frac{V2}{T2}$

Making V2 as the subject formula, we have;

$V_{2}= \frac{V1}{T1} * T_{2}$

$V_{2}= \frac{9.9}{303} * 403$

$V_{2}= 0.0327 * 403$

Final volume, V2 = 13.18 Liters

8 0

3 years ago

A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co

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To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = 10130.0 kPa
V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = 8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
10130 * 50 = n * 8.314 * 573
506500 = 4763.922 n
n = 506500 / 4763.922
n = 106.3199 moles

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4 years ago

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Answer:

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