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docker41 [41]
3 years ago
13

If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.52 m from the base of the

slide, determine the height h (in m) of the water slide.
Physics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

1.80=0+\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.80\times2}{9.8}

t=\sqrt{\dfrac{1.80\times2}{9.8}}

t=0.606\ sec

We need to calculate the velocity

Using formula of velocity

v = \dfrac{d}{t}

Put the value into the formula

v=\dfrac{2.52}{0.606}

v=4.15\ m/s

We need to calculate height

Using conservation of energy

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

Put the value into the formula

h=\dfrac{4.15^2}{2\times9.8}

h=0.878\ m

Hence, The height of the water slide is 0.878 m.

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A penguin slides at a constant velocity of 3.57 m/s down an icy incline. The incline slopes above the horizontal at an angle of
igomit [66]

Answer:t=0.81 s

Explanation:

Given

Penguin slides down with constant velocity of 3.57 m/s

as the Penguin Slides with constant velocity therefore F_{net} is zero on Penguin

F_{net}=mg\sin \theta -f_r

f_r=friction Force

f_r=\mu mg

\mu =coefficient of Kinetic friction

mg\sin \theta =\mu mg

\tan \theta =\mu

\mu =\tan 9.85=0.45

after reaching on floor final velocity of penguin will be zero after time t

thus

v=u+at

here a=\mu g

a=0.45\times 9.8=4.41  (deceleration)

0=3.57-4.41\times t

t=\frac{3.57}{4.41}=0.809

t=0.81 s

8 0
3 years ago
A technician attaches one lead of a digital voltmeter to the ground terminal of the TP sensor and the other meter lead to the ne
wariber [46]

Answer:

Neither A or B

Explanation:

The 37.3mv is not the signal voltage

sensor ground circuit does not has excessive resistance.

5 0
3 years ago
Why is energy required to get an object moving?
xxMikexx [17]

Answer:

this is what popped up when I searched it up:In physics, the kinetic energy (KE) of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

Explanation:

6 0
3 years ago
Read 2 more answers
A stone is launched straight up by a slingshot. Its initial speed is 19.6 m/s, and the stone is 1.50 m above the ground when lau
arlik [135]

Answer: a) 19.21m b) 3.92secs

Explanation:

a) Maximum height reached by the object is the height reached by an object before falling freely under gravity.

Maximum height = U²/2g

U is the initial velocity = 19.6m/s

g is acceleration due to gravity = 10m/s²

Maximum Height = 19.6²/2(10)

H = 19.21m

b) The time elapsed before the stone hits the ground is the time of flight T= 2U/g

T= 2(19.6)/10

T = 39.2/10

Time elapsed is 3.92secs

5 0
3 years ago
A water tank is filled with up to 3.5 m height.Calculate the pressure given by the tank at its bottom​
anyanavicka [17]

Answer:

96.04Pa

Explanation:

height=3.5m

gravity=9.8%

density=9.8/3.5

=2.8

Preassure=h×g×d

=3.5×9.8×2.8

=96.04Pa

6 0
2 years ago
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