Question

A dentist uses a concave mirror to examine a tooth that is 1cm in front of the mirror. The image of the tooth forms 10cm behind the mirror.
a. What is the mirror's radius of curvature?
b. What is the magnification of the image?

Answer 1

a) The mirror's radius of curvature will be 2.7 cm

B)  The magnification of the image will be 4.0.

What is a concave mirror?

When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.

From the mirror equation;

$\frac{1}{p}+\frac{1}{q} =\frac{1}{f} \\\\ \frac{1}{1}+\frac{1}{-10} =\frac{1}{f} \\\\ \frac{1}{f} = 1-\frac{1}{10} \\\\ \frac{1}{f} = \frac{9}{10} \\\\ f= 1.1111$

Hence,

The radius of curvature is twice of the focal length;

$\rm R = 2f \\\\ \rm R = 2\times 1.111 \\\\ R=2.2222 \ cm$

Hence, the mirror's radius of curvature will be 2.7 cm.

The magnification factor is found as;

$\rm m = \frac{-q}{p} \\\\ m = \frac{-(-10)}{1} \\\\ m = 10$

Hence, the magnification of the image will be 4.0.

To learn more about the concave mirror, refer to the link;

brainly.com/question/25937699

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