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forsale [732]
3 years ago
7

A steam catapult launches a jet aircraft from the aircraft carrier john C. Stennis, giving it a peed of 175 mi/h in 2.50 . (a) F

ind the average acceleration of the plane. (b) Assuming the acceleralion is conslant, find lhe dislance the plane moves.
Physics
1 answer:
pentagon [3]3 years ago
3 0

Answer

given,

Speed of the Aircraft,v = 175 mi/h

1 mi/h = 0.44704 m/s

175 mi/h = 78.232 m/s

time, t = 2.5 s

a) average acceleration = ?

a= \dfrac{v - u}{t}

a= \dfrac{78.232 - 0}{2.5}

a = 31.29 m/s²

b) Distance traveled by the Pane

using equation of motion

v² = u² + 2 a s

78.232² = 0² + 2 x 31.29 x s

s = 97.79 m

Distance moved by the plane is equal to 97.79 m

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In what ways would organisms living in very deep water need to be specialized?
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Organisms living in great depths of water bodies like oceans and lakes need to be adapted for two (2) things especially; high water pressure and vision in darkness

The water column above from deep in the water can cause lots of hydrostatic pressure on the organisms’ cells. Also the fact that light cannot penetrate to great depth of water due to diffusion means the organisms must live in darkness.

Explanation:

It has been shown that cells from Piezophile bacteria have a high percentage of fatty acids in their membranes to prevent the cells from compacting solid from the high pressure.

Most of the organisms are also detritivores and use chemosynthesis for the autotrophs because light cannot reach these depths and hence photosynthesis is not possible.  Organisms with eye vision are adapted to high wavelength light that can at least reach greater depths before diffusing. Nonetheless natural selection would favour use of sight for most organisms in this benthic region.

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8 0
3 years ago
A close coiled helical spring of round steel wire 10 mm diameter having 10 complete turns with a mean radius of 60 mm is subject
kow [346]

Answer:

The deflection of the spring is 34.56 mm.

Explanation:

Given that,

Diameter = 10 mm

Number of turns = 10

Radius_{mean} = 60\ mm

Diameter_{mean} = 120\ mm

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We need to calculate the deflection

Using formula of deflection

\delta=\dfrac{8pD^3n}{Cd^4}

Put the value into the formula

\delta=\dfrac{8\times200\times(120)^3\times10}{80\times10^{3}\times10^4}

\delta =34.56\ mm

Hence, The deflection of the spring is 34.56 mm.

4 0
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An average hole drift velocity of 103 cm/sec results when 2 V is applied across a 1 cm long semiconductor bar. What is the hole
Helga [31]

Answer:

ε = 2 V/cm

Explanation:

To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:

ε = ΔV / L

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L: Length of the bar

We already have the voltage and the length so replacing in the above expression we have:

ε = 2 V / 1 cm

<h2>ε = 2 V/cm</h2><h2></h2>

The data of the speed can be used for further calculations, but in this part its not necessary.

Hope this helps

8 0
3 years ago
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