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Lapatulllka [165]
3 years ago
12

For each resource, list 3 examples of how it would be used to produce a hamburger. Think outside of the “hamburger” box!

Engineering
1 answer:
Olin [163]3 years ago
7 0

Answer:

love

Explanation: you

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BlackZzzverrR [31]
I’m guessing This Is Free points? I love That book
6 0
3 years ago
Read 2 more answers
Determine the angles made by the vector V = - 36i + 15j with the positive x- and y-axes. Write the unit vector n in the directio
Nata [24]

Answer:

  157.38° CCW from +x axis

  67.38° CCW from +y axis

  n = (12/13)i +(5/13)j

Explanation:

The reference angle is ...

  arctan(15/36) ≈ 22.62° . . . . CW from the -x axis

The signs of the component vectors indicate this is a 2nd-quadrant vector, so the angles of interest are ...

  157.38° CCW from +x axis

  67.38° CCW from +y axis

The unit vector will be ...

  n = cos(157.38°)i +sin(157.38°)j

 n = (12/13)i +(5/13)j

4 0
3 years ago
Ayo, how do I change my username on here?
nydimaria [60]

Answer:

I'm not sure

Explanation:

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4 0
4 years ago
A gas is compressed isothermally in a piston-cylinder assembly from 7.6 bar, 77 °C to 3.05 bar. Determine the work and heat tran
yaroslaw [1]

Answer:

The work done or the heat transfer for air and hydrogen are 91.71 kj/kg and 1317.89 kj/kg respectively.

Explanation:

Given:

Initial pressure is 7.6 bar.

Initial temperature is 77 °C.

Final pressure is 3.05 bar.

Calculation:

(a)

Take air as an ideal gas with gas constant 0.287 kj/kgK.  

Step1

For isothermal process work done and heat transfer is the same because of no change in internal energy.

Work done is calculated as follows:

W=RT_{1}ln\frac{P_{1}}{P_{2}}

W=0.287(77+273)ln\frac{7.6}{3.05}

W = 91.71 kj/kg.

Thus, the work done or the heat transfer for isothermal process is 91.71 kj/kg.

Step2

For isothermal process work done and heat transfer is the same because of no change in internal energy. Take Hydrogen as an ideal gas with gas constant 4.1242 kj/kgK.

Work done is calculated as follows:

W=RT_{1}ln\frac{P_{1}}{P_{2}}

W=4.1242(77+273)ln\frac{7.6}{3.05}

W = 1317.89 kj/kg.

Thus, the work done or the heat transfer for isothermal process is 1317.89 kj/kg.

4 0
3 years ago
Given the system of equations−3x2+7x3=2,x1+2x2–x3=3,5x1−2x2=2(a). Compute the determinant. (b). Use Cramer’s rule to solve for t
34kurt

Answer:

(x1,x2,x3)=(0.985507,1.463768,0.913043)

Explanation:

<em>note: </em>

<em>solution is provided in word document please find the attached document.</em>

Download docx
5 0
3 years ago
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