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2 years ago

The accuracy of a series of measurements is best understood by looking at the

Physics

1 answer:

bonufazy [111]2 years ago

4 0

The accuracy of a series of measurements is best understood by looking at the known value.

The values obtained in a series of measurement can be precise or accurate.

The precision of the measurement is obtained by looking at the trend of the values obtained.

If the values are close to each other, the measurement is precise but if the values are far from each other, the measurement is not precise.

The accuracy of a measurement is determine by comparing the determine value against a known value.

If the measured value is close to a known value, then the measurement is accurate, but if the measured value is from from a known value then the measurement is not accurate.

Thus, the accuracy of a series of measurements is best understood by looking at the known value.

Learn more here: brainly.com/question/13688896

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To test the performance of its tires, a car

velikii [3]

Answer:

The coefficient of static friction between the tires and the road is 1.987

Explanation:

Given:

Radius of the track, r = 516 m

Tangential Acceleration $a_r$ = 3.89 m/s^2

Speed,v = 32.8 m/s

To Find:

The coefficient of static friction between the tires and the road = ?

Solution:

The radial Acceleration is given by,

$a_{R = \frac{v^2}{r}$

$a_{R = \frac{(32.8)^2}{516}$

$a_{R = \frac{(1075.84)}{516}$

$a_{R = 2.085 m/s^2$

Now the total acceleration is

$\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2$

=> $= \sqrt{ (a_r)^2+(a_R)^2}$

=> $\sqrt{ (3.89 )^2+( 2.085)^2}$

=> $\sqrt{ (15.1321)+(4.347)^2}$

=> $19.4791 m/s^2$

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of static friction is

$\mu =\frac{f}{W}$

From (1) and (2)

$\mu =\frac{ma}{mg}$

$\mu =\frac{a}{g}$

Substituting the values, we get

$\mu =\frac{19.4791}{9.8}$

$\mu =1.987$

8 0

3 years ago

Which of the following equations describes Newton’s second law

svp [43]

C.

Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a

8 0

2 years ago

Read 2 more answers

• 2. A 70 kg man on a 100 kg boat throws a ball. The boat moves backwards 5 meters in 10 seconds. What is

Kipish [7]

Answer:

0.5 m/sec

Explanation:

v=S÷t

=5÷10

v=0.5 m/sec

6 0