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Tanzania [10]
3 years ago
5

Python lists are commonly used to store data types. Lists are a collection of information typically called a container. Think of

a physical container that can hold all kinds of objects, not just one object of the same type. Python includes a built-in list type called a list. They can be managed by many built-in functions that help fill, iterate over, add to, and delete a list. Why is it useful to store information with different data types?
Engineering
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

Explained

Explanation:

Data Type specifies the processor how much amount of memory to be reserved for  a variable.

For example :If a variable is declared as String or Integer this tells the processor  to stored this much of space for this variable to store the value.

List :

1.List is sort of an array used to store values of different data types

2.Lists are ordered .Element in the list are elements in a list are indexed according to a definite sequence and placed at a specific index.Lists can hold different data types.

Here is an example of List ,List = ['a', 1,'b',4,[a,b,c,1]

1. Dictionary is an dis ordered collection of data values, used to store data values .

2.Dictionary is for key,value maps , Keys of a Dictionary are (should be ) unique and of immutable data type such as Strings, Integers and tuples.

Dict = {1: 'Apple', 2: 'Boy', 3:'God',4:[1, 2, 3, 4]}

Each unique key holds a value.  So it depends on the requirement or scenarios where we have to chose between list or dictionary

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Problem definition
LekaFEV [45]

Answer:

ummm thats alot

Explanation:

8 0
2 years ago
The total solids production rate in an activated sludge aeration tank is 7240 kg/d on a dry mass basis. It is necessary to maint
snow_lady [41]

Answer:

volume of biological sludge = 28.566 m³ per day

Explanation:

given data

mass of solid = 7240 kg/day

initial moisture content = 78%

solution

here percentage of solid will be

% of solid = 100 - initial moisture content

% of solid = 100 - 78 = 22 %

so that

mass of sludge produced = \frac{100}{100 - P} M kg  per day

put her value

mass of sludge produced = \frac{100}{100 - 78} 7240 kg

mass of sludge produced = 32909.09 kg

so

specific gravity of sludge =  \frac{\rho sludge}{\rho water }

and as we know that

\frac{100}{S sludge} = \frac{solid percentage}{S solid} = \frac{water percentage}{S water}

\frac{100}{S sludge} = \frac{22}{2.5} = \frac{78}{1}

S sludge = 1.152

so that

density of sludge = S sludge × density of water

density of sludge = 1.152 × 1000

density of sludge = 1152 kg/m³

so that

volume of biological sludge = \frac{mass sludge produce}{\rho sludge}

volume of biological sludge = \frac{32909.09}{1152}

volume of biological sludge = 28.566 m³ per day

6 0
3 years ago
Which of these fuel injection systems operates with fuel injectors located only in the intake manifold near each intake
Stella [2.4K]

Answer:

C. Multipoint fuel injection

Explanation:

A fuel injection system can be defined as a system found in the engine of most automobile cars, used for the supply of a precise amount of fuel or fuel-air mixture to the cylinders in an internal combustion engine through the use of an injector.

There are different types of fuel injection system and these includes;

I. Central-point injection.

II. Throttle (single point) body injection.

III. Gasoline direct injection.

IV. Multipoint (port) fuel injection.

Multipoint fuel injection is a type of fuel injection system that operates with fuel injectors located only in the intake manifold near each intake valve and sprays fuel toward the valve. As a result, it allows for the supply of a precise amount of fuel and as such creating a better air-fuel ratio for automobile cars.

8 0
2 years ago
The drag coefficient of a car at the design conditions of 1 atm, 25°C, and 90 km/h is to be determined experimentally in a large
SIZIF [17.4K]

Answer: 0.288

Explanation:

Given

Pressure of the car, P = 1 atm

Temperature of the car, T = 25° C

Speed of the car, v = 90 km/h = 90*1000/3600 = 25 m/s

Height of the car, h = 1.25 m

Width of the car, b = 1.65 m

Force acting on the far, F = 220 N

Drag coefficient, C(d) = ?

Using our table A-9, we can trace that the density of air ρ, at the given temperature and pressure of 25 °C and 1 atm, is 1.184 kg/m³

Area = h *b

Area = 1.25 * 1.65

Area = 2.0625 m²

Now we solve for the drag coefficient using the formula

C(d) = F / (1/2 * ρ * A * v²)

C(d) = 220 / (0.5 * 1.184 * 2.0625 * 25²)

C(d) = 220 / (1.221 * 625)

C(d) = 220 / 763.125

C(d) = 0.288

Therefore, the drag coefficient is 0.288

3 0
2 years ago
In a major human artery with an internal diameter of 5mm, the flow of blood, averaged over the cardiac cycle is 5cm3·s−1. The ar
antiseptic1488 [7]

9514 1404 393

Answer:

  see attached

Explanation:

Assuming flow is uniform across the cross section of the artery, the mass flow rate is the product of the volumetric flow rate and the density.

  (5 cm³/s)(1.06 g/cm³) = 5.3 g/s

If we assume the blood splits evenly at the bifurcation, then the downstream mass flow rate in each artery is half that:

  (5.3 g/s)/2 = 2.65 g/s

__

The average velocity will be the ratio of volumetric flow rate to area. Upstream, that is ...

  (5 cm³/s)/(π(0.25 cm)²) ≈ 25.5 cm/s

Downstream, we have half the volumetric flow and a smaller area.

  (2.5 cm³/s)/(π(0.15 cm)²) ≈ 35.4 cm/s

7 0
2 years ago
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